The correct answer is the last statement.
If the regulatory serine is mutated to alanine, then acetyl-CoA carboxylase will get activated spontaneously and will produce malonyl-CoA. The increased concentrations of malonyl-CoA will obstruct the oxidation of fatty acids by preventing the entry of fatty acids into the mitochondria.
It is because the AMP-activated protein kinase phosphorylates the serine residues of acetyl-CoA carboxylase to inactivate it. If a mutation occurs in such residues, then the AMPL cannot phosphorylate acetyl-CoA carboxylase and this enzyme will get activated spontaneously.
In such a situation, there will be more than sufficient production of malonyl-CoA, which will inhibit the admittance of more fatty acid getting inside the mitochondria; this will indirectly prevent the oxidation of fatty acids.
When one of the many pigments in the photosystem II absorbs light, the energy is directed inward from pigment to pigment until and unless it reaches the center of reaction. There, energy is conducted towards P680, thus, boosting an electron to a higher level of energy.
Answer: Assuming you mean 'Which of the following is the correct complementary RNA strand?' The answer is D.
Explanation: This is because RNA is A=U G=C T=A
The right option is; D) mitosis
In multicellular organisms, life begins as a single cell until mitosis occurs, causing growth.
Mitosis is a process of cell division, and a part of the cell cycle in which a single cell divides, and produces two identical daughter cells (new nuclei) that contains the same shares of the parent’s cell part. Mitosis occurs in multi cellular organisms, and its primary purpose is for growth, and to replace worn out cells. Mitosis contains four basic stages which are; prophase, metaphase, anaphase, and telophase.
