1) x³ + 2x² - x - 2 2) 2x³ + 5x² - 8x - 20 = 0
x²(x + 2) - (x + 2) x²(2x + 5) - 4(2x + 5) = 0
(x + 2)(x² - 1) (2x + 5)(x² - 4) = 0
(x + 2)(x - 1)(x + 1) x = -5/2, +-2
x = -2, 1, -1 << a is the answer.
hope that helps, God bless!
(-3,2)(1,2)...notice that the y values are the same.....when the y values are the same u have a horizontal line with a 0 slope.
IF the x values would have been the same (instead of the y values), then u would have had a vertical line with an undefined slope.
<h3>Answer:</h3>
room 3 or 4
<h3>Explanation:</h3>
We assume the inequalities tell the rooms that were checked and found empty.
The solution to 3) is ...
... 2x + 3 > 11
... 2x > 8 . . . . . subtract 3
... x > 4 . . . . . . .divide by 2
The solution to 4) is ...
... -3x > -9
... x < 3 . . . . . . divide by -3
Thus, rooms greater than 4 and less than 3 were found empty. Rooms 3 and 4 were not checked, so either one could hold Nessie.
_____
The other inequalities have solutions that are already covered by the solutions to these.
1) x < -1 . . . . after subtacting 4
2) x > 5 . . . . after multiplying by 5
6, if I get it wrong them I'm sorry
The function f(x) = 2|x – 2| + 6 has a vertex at (2, 6) option second is correct.
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have a function that has vertex at (2, 6)
The options are:
f(x) = 2|x – 2| – 6
f(x) = 2|x – 2| + 6
f(x) = 2|x + 2| + 6
f(x) = 2|x + 2| – 6
As we know the vertex form of a quadratic function is given by:
f(x) = a(x - h)² + k
Similarly, mod function can be expressed as:
m(x) = a|x - h| + k
Here (h, k) is the vertex of a function.
In the function:
f(x) = 2|x – 2| + 6
The vertex of the function is (2, 6)
Thus, the function f(x) = 2|x – 2| + 6 has a vertex at (2, 6) option second is correct.
Learn more about the function here:
brainly.com/question/5245372
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