<em><u>HOPE</u></em><em><u> </u></em><em><u>THIS</u></em><em><u> </u></em><em><u>WILL</u></em><em><u> </u></em><em><u>HELP</u></em><em><u> </u></em><em><u>YOU</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Step-by-step explanation:
<h2>b⁸ ( 32b⁵)</h2>
<h2>
that's all</h2><h2>
your answer</h2>
Question: solve for r: 6 ^ (2r) = 800
Answer: 1.87
Step-by-step explanation:
6 ^ (2r) = 800
log(6 ^ (2r)) = log(800)
2r log(6) = log(800)
r = log(800) / (2 log(6))
r = 1.86537641979
round
r = 1.87
log can be any logarithm function.
6^(2×1.86) = 784.734328546
6^(2×1.87) = 813.365367336
I’m not sure but it’s either going to be b or c
Let Kamil get x. Therefore Sean would get (x + 56).
Kamil and Sean are in the ratio: 3:5
That means: x : (x + 56) = 3 : 5
x / (x + 56) = 3/5
5*x = 3*(x + 56)
5x = 3*x + 3*56
5x = 3x + 168
5x - 3x = 168
2x = 168
x = 168 / 2
x = 84
Therefore Kamil had, x = 84, and Sean had (x + 56) = 84 + 56 = 140
Kamil had $84 and Sean had $140
