What is the Domain of the following function?

Given that x is an even number, express, in terms of x, the product of the next two odd numbers.

wariber [46]

Answer:

Odd is the answer.

Step-by-step explanation:

An even number can be written in the form 2x, where x is an integer.

An odd number can be written in the form 2x + 1, where x is an integer.

So two odd numbers can be represented by 2a +1 and 2b +1, the product would be:

(2a + 1)(2b +1) = 4ab + 2a + 2b + 1 = which can be written as 2(2ab + a +b) + 1, but 2ab +a + b represents some integer, so 2ab + a + b = x.

So (2a + 1)(2b + 1) = 2(2ab + a + b ) + 1 = 2x +1 which is odd.

6 0

3 years ago

Please help ASAP 30 pts + brainliest to right/best answer

Delicious77 [7]

When adding two together multiply:

log2 6 + log2 2 = log2(6*2) = log2 12

When you subtract 2 logs, divide:

So you have log2 12 / log2 8

Rewrite as log2 12/8

Simplify to get log2 3/2

The answer is C.

4 0

4 years ago

Read 2 more answers

A pool is filled at a rate of 105gal/min. What is the rate in ml per second

nignag [31]

105 gallons/minute = 6,632.50 mL / second

3 0

3 years ago

H(x)=-x^2+6x. So what is the value of h(2)

crimeas [40]

✩ Answer:

✧･ﾟ: *✧･ﾟ:*✧･ﾟ: *✧･ﾟ:*✧･ﾟ: *✧･ﾟ:*

$\bold{Hello!}\\\bold{Your~answer~is~below!}$

✩ Step-by-step explanation:

✧･ﾟ: *✧･ﾟ:*✧･ﾟ: *✧･ﾟ:*✧･ﾟ: *✧･ﾟ:*

✺ Quadratic polynomials can be factored using the transformation $ax^2+bx+c=a(x-x_{1})(x-x_{2} )$ , where $x_{1}$ and $x_{2}$ are the solutions of the quadratic equation $ax^2+bx+c=0$ :

$-x^2+6x=0$

✺ All equations of the form $ax^2+bx+c=0$ can be solved using the quadratic formula:

$-b=\frac{+}\\\sqrt{b^2-4ac}\\~~~~~~~~~~~~~2a$

✺ The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction:

$x=\frac{\sqrt{-6\frac{+}\\\sqrt{6^2}}}{2(-1)}$

✺ Take the square root of $6^2$ :

$x=\frac{\sqrt{-6\frac{+}\\{6}}}{2(-1)}$

✺ Multiply $2$ times $-1$ :

$x=\frac{\sqrt{-6\frac{+}\\{6}}}{-2}$

✺ Now solve the equation $x=\frac{\sqrt{-6\frac{+}\\{6}}}{-2}$ when ± is plus. Add $-6$ to $6$ :

$x=\frac{0}{-2}$

✺ Divide $0$ by $-2$ :

$x=0$

-OR-

✺ Now solve the equation $x=\frac{\sqrt{-6\frac{+}\\{6}}}{-2}$ when ± is minus. Subtract $6$ from $-6$ :

$x=\frac{-12}{-2}$

✺ Divide $-12$ by $-2$ :

$x=6$

✺ Optional : Factor the original expression using $ax^2+bx+c=a(x-x_{1})(x-x_{2} )$ . Substitute $0$ for $x_{1}$ and $6$ for $x_{2}$ :

$-x^2+6x=-x(x-6)$

✩ Answer:

✺ Factored Form: $x(x-6)$

✺ Exact Form: $x=6$

✺ Graph Point Form: $x=(6,0)$

$Hope~this~helps~and,\\Best~of~luck!\\\\~~~~~-TotallyNotTrillex$

"ටᆼට"

8 0

4 years ago

Write the equation of the line that passes through the points (8, –1) and (2, –5) in standard form, given that the point-slope f

Shkiper50 [21]

The standard form is pretty much the variables on the left-hand-side and the constant alone by herself on the right-hand-side, with only positive integers on the x-variable and an integers all around.

$\bf y+1=\cfrac{1}{2}(x-8)\implies y+1=\cfrac{1}{2}x-4\implies y=\cfrac{1}{2}x-5
\\\\\\
-\cfrac{1}{2}x+y=-5\implies \stackrel{\textit{multiplying both sides by -1}}{\cfrac{1}{2}x-y=5}
\\\\\\
\stackrel{\textit{and multiplying both sides by the LCD 2}}{x-2y=10}\impliedby standard~form$

3 0

4 years ago