Answer: Period: 4. Amplitude: 3
Step-by-step explanation: The period is how long it takes for one cycle of the function (one up and down). In this graph, one cycle ends at 4.
The amplitude is how far away the extremes of the graph are from the midline. This graph is a total of 6 units tall, making the amplitude 3. (I usually find total graph height and divide by 2.)
After every drop,the ball bounces to half it's previous height. With that understood.
1st drop -The ball drops 10m
1st bounce - 5m up
2nd drop - 5m down
2nd bounce - 2.5m up
3rd drop - 2.5m down
3rd bounce - 1.25m up
4th drop - 1.25m down
4th bounce - 0.625m up
5th/last drop - 0.625m down
To find the total vertical distance, you add them all.
10+5+5+2.5+2.5+1.25+1.25+0.625+0.625
=29.25m travelled in all.
If I did the math correctly I’d should be -5 or rewritten as -5/1.
Answer: yes it is indeed your very smart
Answer:
cot theta = -√3
Step-by-step explanation:
we are given that cos theta = - √3/2 within the range 180° < theta < 270° and
since cos theta = adj/hyp
adj = - √3
hyp = 2
Get the opposite using the pythagoras theorem
hyp^2 = opp^2 + adj^2
2² = opp² + (-√3)²
4 = opp² + 3
opp² = 4-3
opp² = 1
opp = 1
tan theta = opp/adj
tan theta = - 1/√3
Recall that cot theta = 1/tan theta
cot theta = 1/(-1/√3)
cot theta = -√3
