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zheka24 [161]
3 years ago
7

Designations at the end of file names such as .docx and .html are called

Computers and Technology
1 answer:
Amanda [17]3 years ago
7 0

Answer:

Designations at the end of file names such as .docx and .html are called. File extensions.

Explanation:

You might be interested in
5.17 (Calculating Sales) An online retailer sells five products whose retail prices are as follows: Product 1, $2.98; product 2,
Dima020 [189]

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

   

    //Initialize the prices as constants

    final double PRODUCT_1_PRICE = 2.98;

    final double PRODUCT_2_PRICE = 4.50;

    final double PRODUCT_3_PRICE = 9.98;

    final double PRODUCT_4_PRICE = 4.49;

    final double PRODUCT_5_PRICE = 6.87;

   

    //Declare the other variables

    int productNumber, quantitySold;

    double total = 0.0;

   

    //Create a Scanner object to get input

    Scanner input = new Scanner(System.in);

   

    //Create a while loop

    while(true){

        //Ask the user to enter the productNumber

     System.out.print("Enter the product number or 999 to quit: ");

     productNumber = input.nextInt();

     

     // Stop the loop, if productNumber is 999(sentinel value, you may choose any value you want)

     if(productNumber == 999)

         break;

     

     //Ask the user to enter the quantitySold

     System.out.print("Enter the quantity sold: ");

     quantitySold = input.nextInt();

     

     //Create a switch statement that works depending on the productNumber entered.

     //For example, if the productNumber is 1, it multiplies the quantitySold by PRODUCT_1_PRICE

     //   and adds the result to the total. If productNumber is 2, it does the same for product 2 ...

     switch(productNumber){

         case 1:

             total += quantitySold * PRODUCT_1_PRICE;

             break;

         case 2:

             total += quantitySold * PRODUCT_2_PRICE;

             break;

         case 3:

             total += quantitySold * PRODUCT_3_PRICE;

             break;

         case 4:

             total += quantitySold * PRODUCT_4_PRICE;

             break;

         case 5:

             total += quantitySold * PRODUCT_5_PRICE;

             break;

     }

    }

 

 //Print the total (when the loop is done)

 System.out.println("The total is $" + total);

}

}

Explanation:

*The code is in Java.

You may see the explanation as comments in the code.

4 0
3 years ago
Successful Web sites such as StumbleUpon ( www.stumbleupon) and Digg ( www.digg) use ____ by inviting their visitors to vote on
aliina [53]

Answer:

"Crowdsourcing" is the correct answer for the above question.

Explanation:

  • Crowdsourcing is a term from which any organization advertises the thinks or can get the ideas or solutions for any particular problem.
  • It is a term that refers to the problem to the number of solvers to achieve the result correct and frequent.
  • For example, If anyone wants to prepare the two websites. Then he assigns the works to the number of people and the works done faster with the help of this.
  • The above question states that some websites can be successful with the help of the type of work. They are successful with the help of crowdsourced work. Because it saves time. So the answer is Crowdsourcing.
3 0
3 years ago
Assume that a large number of consecutive IP addresses are available starting at 198.16.0.0 and suppose that two organizations,
Fiesta28 [93]

Answer & Explanation:

An IP version 4 address is of the form w.x.y.z/s

where s = subnet mask

w = first 8 bit field, x = 2nd 8 bit field, y = 3rd 8 bit field, and z = 4th 8 bit field

each field has 256 decimal equivalent. that is

binary                                        denary or decimal

11111111      =        2⁸      =             256

w.x.y.z represents

in binary

11111111.11111111.11111111.11111111

in denary

255.255.255.255

note that 255 = 2⁸ - 1 = no of valid hosts/addresses

there are classes of addresses, that is

class A = w.0.0.0 example 10.0.0.0

class B = w.x.0.0 example 172.16.0.0

class C = w.x.y.0 example 198.16.8.1

where w, x, y, z could take numbers from 1 to 255

Now in the question

we were given the ip address : 198.16.0.0 (class B)

address of quantity 4000, 2000, 8000 is possible with a subnet mask of type

255.255.0.0 (denary) or

11111111.11111111.00000000.00000000(binary) where /s =  /16 That is no of 1s

In a VLSM (Variable Length Subnet Mask)

Step 1

we convert the number of host/addresses for company A to binary

4000 = 111110100000 = 12 bit

step 2 (subnet mask)

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11110000.000000                /20

now we have added 4 1s in the 3rd field to reserve 12 0s

<u><em>subnet mask: 255.255.</em></u><u><em>16.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1       1      </em></u><u><em> 1 </em></u><u><em>      1     1     1     1</em></u>

<u><em>128  64     32    </em></u><u><em>16</em></u><u><em>    8    4     2    1</em></u>

step 3

in the ip network address: 198.16.0.0/19 <em>(subnet representation)</em> we increment this using 16

that is 16 is added to the 3rd field as follows

That means the ist Valid Ip address starts from

          Ist valid Ip add: 198.16.0.1 - 198.16.15.255(last valid IP address)

Company B starts<u><em>+16: 198.16.</em></u><u><em>16</em></u><u><em>.0 - 198.16.31.255</em></u>

<u><em>                   +16: 198.16.</em></u><u><em>32</em></u><u><em>.0- 198.16.47.255 et</em></u>c

we repeat the steps for other companies as follows

Company B

Step 1

we convert the number of host/addresses for company B to binary

2000 = 11111010000 = 11 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 11 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11111000.000000                /21

now we have added 5 1s in the third field to reserve 11 0s

<u><em>subnet mask: 255.255.</em></u><u><em>8.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1       1       1       </em></u><u><em>1 </em></u><u><em>    1     1     1</em></u>

<u><em>128  64     32    16    </em></u><u><em>8 </em></u><u><em>   4     2    1</em></u>

Step 3

Starting from after the last valid Ip address for company A

in the ip network address: 198.16.16.0/21 (<em>subnet representation</em>) we increment this using 8

That means the ist Valid Ip address starts from

           Ist valid Ip add: 198.16.16.1 - 198.16.23.255(last valid IP address)

Company C starts <u><em>+16: 198.16.</em></u><u><em>24</em></u><u><em>.0- 198.16.31.255</em></u>

<em>                             </em><u><em> +16: 198.16.</em></u><u><em>32</em></u><u><em>.0- 198.16.112.255 et</em></u>c

Company C

Step 1

we convert the number of host/addresses for company C to binary

4000 = 111110100000 = 12 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11110000.000000                /20

now we have added 4 1s in the 3rd field to reserve 12 0s

<u><em>subnet mask: 255.255.</em></u><u><em>16.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1       1       1       1     1     1     1</em></u>

<u><em>128  64     32    16    8    4     2    1</em></u>

Step 3

Starting from after the last valid ip address for company B

in the ip network address: 198.16.24.0/20 (subnet representation) we increment this using 16

That means the ist Valid Ip address starts from

           Ist valid Ip add: 198.16.24.1 - 198.16.39.255(last valid IP address)

Company C starts <u><em>+16: 198.16.40.0- 198.16.55.255</em></u>

<em>                          </em><u><em>    +16: 198.16.56.0- 198.16.71.255 et</em></u>c

Company D

Step 1

we convert the number of host/addresses for company D to binary

8000 = 1111101000000 = 13 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 13 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11100000.000000                /19

now we have added 3 1s in the 3rd field to reserve 13 0s

<u><em>subnet mask: 255.255.</em></u><u><em>32.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1      </em></u><u><em> 1 </em></u><u><em>      1       1     1     1     1</em></u>

<u><em>128  64     </em></u><u><em>32  </em></u><u><em>  16    8    4     2    1</em></u>

Step 3

Starting from after the last valid ip address for company C

in the ip network address: 198.16.40.0/20 (subnet representation) we increment this using 32

That means the ist Valid Ip address starts from

           Ist valid Ip add: 198.16.40.1 - 198.16.71.255(last valid IP address)

Company C starts <u><em>+16: 198.16.72.0- 198.16.103.255</em></u>

<em>                          </em><u><em>    +16: 198.16.104.0- 198.16.136.255 et</em></u>c

5 0
3 years ago
Given a String variable named sentence that has been initialized, write an expression whose value is the number of characters in
Troyanec [42]
Python:

sentence = “this is the sentence.”
size = len(sentence)

C++:

string sentence = “this is the sentence.”
int size = sentence.size()

* Remember strings are just arrays of characters.

5 0
3 years ago
A database that is created and maintained using services such as Microsoft Azure or Amazon AWS is called a(n) _____ database.
Phantasy [73]

Answer:

It is called a cloud database

5 0
3 years ago
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