I think maybe 3) would make the most sense because she wants a random sample of students and the other options are specific on the type of students.
Answer: 17 is A and 18 is B
Used a calculator to add them all up! Get some sleep hope this helps.
17) 2(3x8)+2(3x6)+2(6x8) = 180
18) 4(9x2)+2(9x9) = 234
Boys are b
Girls are g
b + g = 120
2g = b
Substitute the second equation into the first
2g + g = 120
3g = 120
g = 40
Plug in g = 40 and solve for b
b + g = 40
b + 40 = 120
b = 80
There are 40 girls and 80 boys.
Answer:
y = -4/5x + 3
Step-by-step explanation:
Chose any two points on the line:
(5, -2)
(-5, 6)
Slope = (y2 - y1) / (x2 - x1)
6 -(-2) / -5 - 5
8 / -10
-4/5
Equation:
y = mx + b
Plug in x and y using any coords and then plug in m (the slope):
-2 = -4/5 * 5 + b
-2 = -20/4 + b
-2 = -5 + b
Add 5 on both sides:
3 = b
Now our equation is:
y = -4/5x + 3
Please let me know if I've done something wrong!
Answer/Step-by-step explanation:
Question 1:
Interior angles of quadrilateral ABCD are given as: m<ABC = 4x, m<BCD = 3x, m<CDA = 2x, m<DAB = 3x.
Since sum of the interior angles = (n - 2)180, therefore:

n = 4, i.e. number of sides/interior angles.
Equation for finding x would be:



(dividing each side by 12)

Find the measures of the 4 interior angles by substituting the value of x = 30:
m<ABC = 4x
m<ABC = 4*30 = 120°
m<BCD = 3x
m<BCD = 3*30 = 90°
m<CDA = 2x
m<CDA = 2*30 = 60°
m<DAB = 3x
m<DAB = 3*30 = 90°
Question 2:
<CDA and <ADE are supplementary (angles on a straight line).
The sum of m<CDA and m<ADE equal 180°. To find m<ADE, subtract m<CDA from 180°.
m<ADE = 180° - m<CDA
m<ADE = 180° - 60° = 120°