Answer:
Step-by-step explanation:
let x be the population
so we have ,
2x= 6h
?= 3 days or 3×24h
by cross multiplication we have
2x× 72h= 6h×?
?= 2x×72/6 = 24x
So, in three days the bacteria will b 24 times current population.
Step-by-step explanation:
Given that,
Distance covered by a trucker, d = 500 miles
Average speed of the trucker, v = 600 mph
A trucker drove 500 miles in h hours. We need to write the linear equation used to find the number of hours that the trucker drove. Average speed is given by :

t is time in hours

If t is h hours,

On solving, h = 5 hours.
Hence, this is the required solution.
Based on the calculations, the length of side CM is equal to 4 units.
<h3>How to calculate the
length of side CM?</h3>
First of all, we would determine the measure of angle B by applying the law of cosine as follows:
B² = A² + C² - 2(A)(C)cosB
<u>Given the following data:</u>
A = BC = 5
B = AC = 4√2
C = AB = 7
Substituting the given parameters into the formula, we have;
(4√(2))² = 5² + 7² - 2 × 5 × 7 × cosB
cos(B) = ((4√(2))² - (5² + 7²))/(-2×5×7)
cos(B) = 0.6
B = cos⁻¹(0.6)
B = 53.13°.
Now, we can find side CM by using sine trigonometry:
sin(B) = CM/BC
CM = BC × sin(B)
CM = 5 × sin(53.13°)
CM = 5 × 0.8
CM = 4 units.
Read more on cosine law here: brainly.com/question/11000638
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D. (-3,4)
you need to flip the triangle across the y-axis to find the reflected point of D
Answer:
Probability that at most 50 seals were observed during a randomly chosen survey is 0.0516.
Step-by-step explanation:
We are given that Scientists conducted aerial surveys of a seal sanctuary and recorded the number x of seals they observed during each survey.
The numbers of seals observed were normally distributed with a mean of 73 seals and a standard deviation of 14.1 seals.
Let X = <u><em>numbers of seals observed</em></u>
The z score probability distribution for normal distribution is given by;
Z =
~ N(0,1)
where,
= population mean numbers of seals = 73
= standard deviation = 14.1
Now, the probability that at most 50 seals were observed during a randomly chosen survey is given by = P(X
50 seals)
P(X
50) = P(
) = P(Z
-1.63) = 1 - P(Z < 1.63)
= 1 - 0.94845 = <u>0.0516</u>
The above probability is calculated by looking at the value of x = 1.63 in the z table which has an area of 0.94845.