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Naddika [18.5K]
3 years ago
15

I need help with this question. It is due today and if I email my teacher, she doesn’t respond till 10 pm. So please anyone who

can answer this, I would appreciate it .

Mathematics
2 answers:
dangina [55]3 years ago
4 0

Answer:

Step-by-step explanation: rip this kid aye

SINON2 years ago
1 0

yuki what should i do im scared my hands r going numb

SINON
2 years ago
im scared idk who that person is what if they actually know my parents
Yukiterucutie
2 years ago
It's ok, you could say it was all a lie or I can do what they want so they don't tell on you
SINON
2 years ago
it could be one of my cousins but non of em like bts well expect 1 but she would never tell on me cuz shes like a sis to me
SINON
2 years ago
ok but army said that me and them r enemies
Yukiterucutie
2 years ago
Don't worry we'll figure this out, it could also be someone who stalks our conversations and has found this out about you
Yukiterucutie
2 years ago
I'll talk her out of it
SINON
2 years ago
like we're on bad terms but idk anyone like that
SINON
2 years ago
ok thx
SINON
2 years ago
im scared my dad will kill me
Yukiterucutie
2 years ago
No problem, it was clever of you to think of this no one will find us here
Yukiterucutie
2 years ago
Wait really?
SINON
2 years ago
ignore what im gonna say on the other post
Yukiterucutie
2 years ago
Ok
Yukiterucutie
2 years ago
If you want we can always come back here
SINON
2 years ago
so they don't fallow
SINON
2 years ago
ok but what if they call my parents
SINON
2 years ago
or what if they come to our house or we go to them
Yukiterucutie
2 years ago
Then you can say she's a liar who wants to get you in trouble
SINON
2 years ago
ok
SINON
2 years ago
ill try to erase my history
Yukiterucutie
2 years ago
I'll beg her not get you in trouble, get on her good side, whatever it takes
Yukiterucutie
2 years ago
Ok
SINON
2 years ago
but i don't know if i can erase my account so if that person told them what the website is called they'll find out
SINON
2 years ago
ok
Yukiterucutie
2 years ago
You could beg her not to tell your family
SINON
2 years ago
ok
Yukiterucutie
2 years ago
It'll be ok
SINON
2 years ago
brb
Yukiterucutie
2 years ago
Ok
SINON
2 years ago
im back
Yukiterucutie
2 years ago
Ok
SINON
2 years ago
so they think im in 12th but i would be in 11th rn not 12th
SINON
2 years ago
and all my cousins know im in 10th and i don't have any friends back in fifth grade
Yukiterucutie
2 years ago
Got it, we should mislead them in any way we can
Yukiterucutie
2 years ago
Yea maybe she was just guessing
SINON
2 years ago
yeah maybe
Yukiterucutie
2 years ago
But I have to go for like 20 minutes Ill be back soon
SINON
2 years ago
im just so sacred i can't focus on hw
SINON
2 years ago
if they knew me from way back they would forget me already cuz i was quit back then there is no way they would remember me
SINON
2 years ago
r they a stalker
SINON
2 years ago
the only way they would think that im in 12th means they knew me since i was in saudi arabia cuz when i came here i got held a year back
SINON
2 years ago
they said our parents know each other but do i know their parents or them r they girl or boy
Yukiterucutie
2 years ago
Don't over think it
SINON
2 years ago
ok
Yukiterucutie
2 years ago
It'll be ok, I'm here to help
SINON
2 years ago
thx onii-sama
Yukiterucutie
2 years ago
No, you need it, you don't need to thank me
SINON
2 years ago
ok kokoro posted a new post
Yukiterucutie
2 years ago
Ok
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C. The gardener wants to cover and area of 108 square feet. The height of the garden is 12
Lisa [10]

Answer:A

Step-by-step explanation: You divide 108 by 12

7 0
4 years ago
Geometric Sequence S = 1.0011892 + ... + 1.0012 + 1.001 + 1
leva [86]

Answer:

<em />S_{1893} =5632.98<em />

<em />

Step-by-step explanation:

The correct form of the question is:

S = 1.001^{1892} + ... + 1.001^2 + 1.001 + 1

Required

Solve for Sum of the sequence

The above sequence represents sum of Geometric Sequence and will be solved using:

S_n = \frac{a(1 - r^n)}{1 - r}

But first, we need to get the number of terms in the sequence using:

T_n = ar^{n-1}

Where

a = First\ Term

a = 1.001^{1892}

r = common\ ratio

r = \frac{1}{1.001}

T_n = Last\ Term

T_n = 1

So, we have:

T_n = ar^{n-1}

1 = 1.001^{1892} * (\frac{1}{1.001})^{n-1}

Apply law of indices:

1 = 1.001^{1892} * (1.001^{-1})^{n-1}

1 = 1.001^{1892} * (1.001)^{-n+1}

Apply law of indices:

1 = 1.001^{1892-n+1}

1 = 1.001^{1892+1-n}

1 = 1.001^{1893-n}

Represent 1 as 1.001^0

1.001^0 = 1.001^{1893-n}

They have the same base:

So, we have

0 = 1893-n

Solve for n

n = 1893

So, there are 1893 terms in the sequence given.

Solving further:

S_n = \frac{a(1 - r^n)}{1 - r}

Where

a = 1.001^{1892}

r = \frac{1}{1.001}

n = 1893

So, we have:

S_{1893} =\frac{1.001^{1892} *(1 -\frac{1}{1.001}^{1893})}{1 -\frac{1}{1.001} }

S_{1893} =\frac{1.001^{1892} *(1 -\frac{1}{1.001}^{1893})}{\frac{1.001 -1}{1.001} }

S_{1893} =\frac{1.001^{1892} *(1 -\frac{1}{1.001}^{1893})}{\frac{0.001}{1.001} }

S_{1893} =\frac{1.001^{1892} *(1 -\frac{1}{1.001^{1893}})}{\frac{0.001}{1.001} }

Simplify the numerator

S_{1893} =\frac{1.001^{1892}  -\frac{1.001^{1892}}{1.001^{1893}}}{\frac{0.001}{1.001} }

S_{1893} =\frac{1.001^{1892}  -1.001^{1892-1893}}{\frac{0.001}{1.001} }

S_{1893} =\frac{1.001^{1892}  -1.001^{-1}}{\frac{0.001}{1.001} }

S_{1893} =(1.001^{1892}  -1.001^{-1})/({\frac{0.001}{1.001} })

S_{1893} =(1.001^{1892}  -1.001^{-1})*{\frac{1.001}{0.001}}

S_{1893} =\frac{(1.001^{1892}  -1.001^{-1}) * 1.001}{0.001}

Open Bracket

S_{1893} =\frac{1.001^{1892}* 1.001  -1.001^{-1}* 1.001 }{0.001}

S_{1893} =\frac{1.001^{1892+1}  -1.001^{-1+1}}{0.001}

S_{1893} =\frac{1.001^{1893}  -1.001^{0}}{0.001}

S_{1893} =\frac{1.001^{1893}  -1}{0.001}

S_{1893} =5632.97970294

Hence, the sum of the sequence is:

<em />S_{1893} =5632.98<em> ----- approximated</em>

4 0
3 years ago
How do find the median and range..?<br><br> give examples!
swat32

Answer:

Count how many numbers you have. If you have an odd number, divide by 2 and round up to get the position of the median number. If you have an even number, divide by 2. Go to the number in that position and average it with the number in the next higher position to get the median.

The range is calculated by subtracting the lowest value from the highest value.
Step-by-step explanation:

hope this helped!

7 0
3 years ago
Read 2 more answers
Let R be the region in the first quadrant bounded by the graphs of y =x^2 and y=2x, as shown in the figure above. The region R i
Kobotan [32]

Answer:

The area between the two functions is approximately 1.333 units.

Step-by-step explanation:

If I understand your question correctly, you're looking for the area surrounded by the the line y = 2x and the parabola y = x², (as shown in the attached image).

To do this, we just need to take the integral of y = x², and subtract that from the area under y = 2x, within that range.

First we need to find where they intersect:

2x = x²

2 = x

So they intersect at (2, 4) and (0, 0)

Now we simply need to take the integrals of each, subtracting the parabola from the line (as the parabola will have lower values in that range):

a = \int\limits^2_0 {2x} \, dx - \int\limits^2_0 {x^2} \, dx\\\\a = x^2\left \{ {{x=2} \atop {x=0}} \right - \frac{x^3}{3}\left \{ {{x=2} \atop {x=0}} \right\\\\a = (2^2 - 0^2) - (\frac{2^3}{3} - \frac{0^3}{3})\\\\a = 2^2 - \frac{2^3}{3}\\a = 4 - 8/3\\a \approx 1.333

So the correct answer is C, the area between the two functions is 4/3 units.

3 0
3 years ago
Find all the points having an x-coordinate of 4 whose distance from the point (-2,-1) is 10
Marta_Voda [28]
A(x_1;\ y_1);\ B(x_2;\ y_2)\\\\the\ distance\ between\ A\ and\ B:\\\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\A(-2;-1);\ B(4;\ y);\ d=10\\\\subtitute\\\\\sqrt{(4-(-2))^2+(y-(-1))^2}=10\\\\\sqrt{(4+2)^2+(y+1)^2}=10\\\\\sqrt{6^2+(y+1)^2}=10\\\\\sqrt{36+(y+1)^2}=10\ \ \ |square\ both\ sides\\\\36+(y+1)^2=10^2\\\\36+(y+1)^2=100\ \ \ |subtract\ 36\ from\ both\ sides\\\\(y+1)^2=64\iff y+1=-\sqrt{64}\ or\ y+1=\sqrt{64}\\\\y+1=-8\ or\ y+1=8\ \ \ \ |subtract\ 1\ from\ both\ sides\\\\y=-9\ or\ y=7

Answer:{\boxed{(4;-9)\ or\ (4;\ 7)}
4 0
3 years ago
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