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babymother [125]
2 years ago
5

How do find the median and range..? give examples!

Mathematics
2 answers:
swat322 years ago
7 0

Answer:

Count how many numbers you have. If you have an odd number, divide by 2 and round up to get the position of the median number. If you have an even number, divide by 2. Go to the number in that position and average it with the number in the next higher position to get the median.

The range is calculated by subtracting the lowest value from the highest value.
Step-by-step explanation:

hope this helped!

postnew [5]2 years ago
3 0

Answer:

It is the number in the middle of a set of numbers arranged in ascending order, it will be easier to find median if the set of given numbers are even if its an odd number, then divide the number by 2.

To find the range subtract the lowest value from the highest value

Step-by-step explanation:

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Is algebra.
anzhelika [568]

Step-by-step explanation:

they need to add up to -56

and multiply to 180

4 0
3 years ago
L.C.M of x2 + 3x + 2 and x2 + 4x + 3
lutik1710 [3]

Answer:

Step-by-step explanation:

x^2 + 3x + 2 = (x+1)(x+2)

x^2 + 4x + 3 = (x+1)(x+3)

LCM = (x+1)(x+2)(x+3) = (x^2 + 3x + 2) (x+3) = x^3 + 6x^2 + 11x + 6

4 0
3 years ago
Read 2 more answers
Only 4 please i need it by tomorrow
seraphim [82]
No she is not correct she needs to go back to school and learn math 
8 0
3 years ago
Find the argument of the complex number z=1+iv3
elena-14-01-66 [18.8K]

Given:

The complex number is:

z=1+i\sqrt{3}

To find:

The argument of the given complex number.

Solution:

If a complex number is z=x+iy, then the argument of the complex number is:

\theta=\tan^{-1}\dfrac{y}{x}

We have,

z=1+i\sqrt{3}

Here, x=1 and y=\sqrt{3}. So, the argument of the given complex number is:

\theta =\tan^{-1}\dfrac{\sqrt{3}}{1}

\theta =\tan^{-1}\sqrt{3}

\theta =\tan^{-1}\left(\tan \dfrac{\pi}{3}\right)

\theta =\dfrac{\pi}{3}

Therefore, the argument of the given complex number is \theta =\dfrac{\pi}{3}.

6 0
3 years ago
Three less than one-fourth of the product of eight thirds and nine. Please write equation, then solve.
kenny6666 [7]
Put simply, you have to work backwards in making the equations. Start with the product of 8/3 and 9.
\frac{8}{3}*9

 Next take 1/4 of that. This can be done in two ways, either multiplying by 1/4:
(\frac{8}{3}*9)*\frac{1}{4}

, or dividing everything by 4.
(\frac{8}{3}*9)/4

Finally, subtract three.

The final equation would read:
((\frac{8}{3}*9)*\frac{1}{4})-3



Using PE(M/D)(A/S), we'd start with \frac{8}{3}*9

3 and 9 cancel out to be 1 and 3, leaving us with \frac{8}{1}, or 8, and 3 and this part of the equation reading 8*3, which is 24.

The next step is \frac{24}{4}, which is 6.

Lastly we subtract 3 from six, leaving us 3.
7 0
3 years ago
Read 2 more answers
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