The answer i got is 3.5 rounded
Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
Part 1) Find the area
we know that
The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle
so

we have that the base and the height of triangle is equal to the radius of the circle

substitute

simplify
Factor 36

Part 2) Find the perimeter
The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle
The circumference of a quarter of circle is equal to

substitute the given values

Applying the Pythagorean Theorem
The hypotenuse of right triangle is equal to

simplify

Find the perimeter

simplify
Factor 6

Answer:
squaare root of 70<pi squared<10
Step-by-step explanation:
Talking about square root of 70, you can take the answer by approximation. u know square of eight is sixty four and square of nine is eighty one. so 70's square root shluld be between eight and nine. And as the value of pi is 3.14... when square of pi is considerd it should be >9 but <10 as pi>3. So 10 become te greatest
c.y+3=f(x) and 0+3 therefore x=3
The answer to the question