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Arisa [49]
2 years ago
5

Hi i have no idea does anyone have an idea ? please

Mathematics
1 answer:
ivann1987 [24]2 years ago
3 0

Answer:

y = 2(x+5)²- 60

Step-by-step explanation:

f(x) = ax² +bx +c,  is the standard form

f(x) = a(x - h)² +k , is the vertex form where the (h, k) is the vertex

y = 2x²+20x -10 ,

factor 2 from the two terms

y = 2(x² +10x) -10,

what perfect square has x² +10x? ... x²+10x +25 = (x+5)²

y = 2(x²+10x+25 )- 50 -10,

add 25 in parenthesis to get a perfect square yet subtract 2*25 = 50 so the equation will stay the same

y = 2(x+5)²- 60,

the equation has the vertex at (-5, -60)

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Solve the equation for y<br> Y minus 5 equals 1/3 (x plus 12)
Vinvika [58]

Answer:

ok so this problem you are basically just rearranging it. you're going to want y by itself.

Step-by-step explanation:

let's start with the original equation: 5-y=1/3x +12

so first you have to move the five over, so you subtract 5 from both sides. -y=1/3x+12-5

then you subtract the 5 from the twelve since they're like terms: -y=1/3x+7

and finally you have to move the negative over. when you move the negative think of it like dividing negative one from both sides, everything on the other side has to get the negative.

so we're left with y=-1/3x-7

I hope this helps!

5 0
3 years ago
Please help me!!!! precalc question
dangina [55]

Step-by-step explanation:

1. Ampltiude is 1

The period is

\frac{2\pi}{3}

is the period

The phase shift is 0

2. The Ampltiude is 2

The period is 2 pi

The phase shift is 1

3. The amplitude is 3

The period is 2 pi/3

The phase shift is -2

4.The amplitude is 2/3

The period is -10pi

The phase shift is 0

5. The Ampltiude is 1

The period is -2 pi

The phase shift is pi

6. The amplitude is 1/4

The period is -4pi

The phase shift is negative 2pi/3

7. The Ampltiude is 3

The period is 4

The phase shift is 8

7 0
3 years ago
G(X) = -3/2x<br> Find g(4)
a_sh-v [17]

substitute 4 as x in both sides of the equation

basically multiply -3/2 by 4


5 0
3 years ago
Read 2 more answers
What is the solution to this equation 2/3x+1=1/6×-7
Alika [10]

Answer:

A . x= -16

Step-by-step explanation:

\\\frac{2}{3}x+1=\frac{1}{6}x-7\\\\\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}\\\\\frac{2}{3}x+1-1=\frac{1}{6}x-7-1\\\\\frac{2}{3}x=\frac{1}{6}x-8\\\\\mathrm{Subtract\:}\frac{1}{6}x\mathrm{\:from\:both\:sides}\\\\\frac{2}{3}x-\frac{1}{6}x=\frac{1}{6}x-8-\frac{1}{6}x\\\\= \frac{1}{2}x=-8\\\\\mathrm{Multiply\:both\:sides\:by\:2}\\\\2\times \frac{1}{2}x=2\left(-8\right)\\\\x=-16

7 0
3 years ago
Write the slope-intercept form of the equation of each line given the slope and y-intercept.
saul85 [17]

Answer:

4b. −6x + y = −4

4a. 7x + 4y = −12

3b. y = ½x + 3

3a. y = −6x + 5

2b. y + 2 = −⅔(x + 3)

2a. y - 3 = ⅘(x - 5)

1b. y = -x + 5

1a. y = 5x - 3

Step-by-step explanation:

4.

Plug the coordinates into the Slope-Intercept Formula first, then convert to Standard Form [Ax + By = C]:

b.

2 = 6[1] + b

6

−4 = b

y = 6x - 4

-6x - 6x

_________

−6x + y = −4 >> Standard Equation

a.

4 = −7⁄4[-4] + b

7

−3 = b

y = −7⁄4x - 3

+7⁄4x +7⁄4x

____________

7⁄4x + y = −3 [We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]

4[7⁄4x + y = −3]

7x + 4y = −12 >> Standard Equation

__________________________________________________________

3.

Plug both coordinates into the Slope-Intercept Formula:

b.

5 = ½[4] + b

2

3 = b

y = ½x + 3 >> EXACT SAME EQUATION

a.

−1 = −6[1] + b

−6

5 = b

y = −6x + 5

* Parallel lines have SIMILAR <em>RATE OF CHANGES</em> [<em>SLOPES</em>].

__________________________________________________________

2.

b. y + 2 = −⅔(x + 3)

a. y - 3 = ⅘(x - 5)

According to the <em>Point-Slope Formula</em>, <em>y - y₁ = m(x - x₁)</em>, all the negative symbols give the OPPOSITE TERMS OF WHAT THEY REALLY ARE, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT SIGNS.

__________________________________________________________

1.

b. y = -x + 5

a. y = 5x - 3

Just write out the Slope-Intercept Formula as it is given to you.

I am joyous to assist you anytime.

3 0
3 years ago
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