50 < 8 - 6x
50 - 8 < 6x
42 < 6x
7 < x
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
<h3>What is the least number of buses needed to carry 710 passengers? </h3>
Given that;
- Number of passengers n = 710
- Least number of buses need B = ?
To get the least number of buses, we say;
Number of buses B = 710 ÷ 150
Number of buses B = 4.7 ≈ 5
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
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Answer:
3846.5 is the answers for the question
Step-by-step explanation:
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Answer:
C
Step-by-step explanation:
SD is congruent to PD and both triangles share the same side with each other.
