What is the square root of 64y16? 6 OF O 4y4 4y8 8y4 O O 8y8

Mathematics

2 answers:

alexandr402 [8]3 years ago

7 0

Answer:

8y8

i recomend you to use p.h.o.t.o.m.a.t.h

lyudmila [28]3 years ago

7 0

√(64y^16)

= √64 √(y^16)

= 8 √(y^16)

Using the Radical Rule of exponents:
(n√a^m) = a^(m/n)

= 8•y^(16/2)

= 8y^8

Therefore, the correct answer is 8y^8.

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The equation of line WX is 2x + y = -5. What is the equation of a line perpendicular to line WX in slope-intercept form that con

sveticcg [70]

Answer:

The third choice is the one you want

Step-by-step explanation:

If we are to write the equation of a line perpendicular to WX, we first must determine what the slope of the WX is, because the line perpendicular to WX has a slope that is the flip of the slope of WX with the opposite sign. Solving for y takes care of finding the slope of WX:

2x + y = -5 so

y = -2x - 5

The slope is -2. That means that the reciprocal slope is 1/2. Using that slope along with the coordinates x = -1 and y = -2, we first write the line using point-slope form and then solve it for y. Start by filling in the m, the x value and the y value:

$y - (-2) = \frac{1}{2}(x-(-1))$

Getting rid of the double negatives gives us:

$y+2=\frac{1}{2}(x+1)$

Distributing then gives us:

$y+2=\frac{1}{2}x+\frac{1}{2}$

And finally solving for y (I am going to express the 2 on the left as 4/2 when I move it by subtraction in order to add those fractions):

$y=\frac{1}{2}x+\frac{1}{2}-\frac{4}{2}$

And the final equation in slope-intercept form is:

$y=\frac{1}{2}x-\frac{3}{2}$

8 0

3 years ago

What is the angle measure of an arc bounding sector with an area of 5pie square miles?

Snowcat [4.5K]

if the diameter is 20, the its radius must be half that or 10.

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