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Goshia [24]
3 years ago
12

66666666666666666666666666666666666666666=866666+56565656565656565656565656565656564=

Mathematics
2 answers:
postnew [5]3 years ago
6 0

Answer:

111111111111111111111111122222222222222222222222222222222222222222

Step-by-step explanation:

Gnoma [55]3 years ago
6 0

Answer:

no that's not correct

Step-by-step explanation:

66666666666666666666666666666666666666666 does not equal 866666+56565656565656565656565656565656564

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Find the product of 619 x 37
Vikki [24]

Answer:

22903

Step-by-step explanation:

619\cdot 37=22903. Hope this helps!

3 0
3 years ago
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What are all the keys that must be pressed, in correct order, on the calculator shown to find the value of 462 divided by 3?
Alexandra [31]
The second one, 4 6 2 / 3
6 0
4 years ago
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morgan poured 9/10 liter of punch into each of 6 bottles how many liters of punch did she pour in all
drek231 [11]

Answer:

5 and 2/5 liters     or          5.4 liters

Step-by-step explanation:

9/10 times 6

9 times 6 is 54. 54 divided by 10 is 5.4 which is the same as 5 and 2/5

3 0
3 years ago
at a school concert the total value of tickets sold was $994. Student tickets sold for $5 and adult tickets sold for $8. The num
ValentinkaMS [17]

Answer:

42 student tickets and 98 adult tickets

Step-by-step explanation:

Let's call the number of student tickets 's' and the number of adult tickets 'a'.

Then, we can write the two equations below:

5s + 8a = 994

a = 2s + 14

Using the value of 'a' from the second equation in the first one, we have:

5s + 8*(2s + 14) = 994

5s + 16s + 112 = 994

21s = 882

s = 42

Now, finding the value of 'a', we have:

a = 2*42 + 14 = 98

6 0
4 years ago
Read 2 more answers
Three sisters have ages that are consecutive odd integers. The sum of the age of the youngest and three times the age of the old
kenny6666 [7]

Answer:

youngest   17  

middle  19

oldest    21

Step-by-step explanation:

Three sisters have ages that are consecutive odd integers

youngest = x

middle = x + 2

oldest = x + 4

--------------------

The sum of the age of the youngest

x

and three times the age of the oldest

+ 3(x + 4)

is five less than five times the middle sister’s age

= 5(x + 2) - 5

-----------------------

x + 3(x + 4) = 5(x + 2) - 5

Distribute

x + 3x + 12 = 5x + 10 - 5

Combine like terms

4x + 12 = 5x - 5

Subtract 4x from both sides

12 = x - 5

Add 5 to both sides

17 = x

youngest   x = 17  

middle     x + 2 = 19

oldest     x + 4 = 21

5 0
3 years ago
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