To find the average of an amount of numbers, we simply add them up and divide them by the amount of numbers we have. For example, if we have 1,2, and 3 as our numbers, we can see that we have three numbers. Next, we add them up to get 1+2+3=6. Lastly, we divide 6 by the amount of numbers we have (3) to get 6/3=2 as our average. Applying that here, we see that there are four numbers. Next, we add them up using a calculator to get 5,678.54+3,665.77+4,231.98+4,768.99 =18345.28 . Finally, we divide that number by the amount of numbers we have (using a calculator) to get 18345.28/4=4,586.32, making B your answer.
Feel free to ask further questions, and Happy Halloween!
the solid is made up of 2 regular octagons, 8 sides, joined up by 8 rectangles, one on each side towards the other octagonal face.
from the figure, we can see that the apothem is 5 for the octagons, and since each side is 3 cm long, the perimeter of one octagon is 3*8 = 24.
the standing up sides are simply rectangles of 8x3.
if we can just get the area of all those ten figures, and sum them up, that'd be the area of the solid.
![\bf \textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ a=5\\ p=24 \end{cases}\implies A=\cfrac{1}{2}(5)(24)\implies \stackrel{\textit{just for one octagon}}{A=60} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{two octagon's area}}{2(60)}~~+~~\stackrel{\textit{eight rectangle's area}}{8(3\cdot 8)}\implies 120+192\implies 312](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20regular%20polygon%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dap~~%20%5Cbegin%7Bcases%7D%20a%3Dapothem%5C%5C%20p%3Dperimeter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D5%5C%5C%20p%3D24%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%285%29%2824%29%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bjust%20for%20one%20octagon%7D%7D%7BA%3D60%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwo%20octagon%27s%20area%7D%7D%7B2%2860%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Beight%20rectangle%27s%20area%7D%7D%7B8%283%5Ccdot%208%29%7D%5Cimplies%20120%2B192%5Cimplies%20312)
Let's say "the second number" is y so y= 7(x) And x+y= 32
you would plug in y=7x into x+y=32 and that would look like this....x+7x=32
then you would add the x's and that would look like.... 8x=32 then you would divide 32/8 and get x =4 to find y, you just plug in x=4 into x+y=32
but I did most of the work so you can find y ;)
its not that hard... im sure you can do that;))))
Answer:i think the answer is 15 and 16
Step-by-step explanation:
just use a calculator
The answer to the question is 90
