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Snowcat [4.5K]
2 years ago
11

Please help! X=? AB=? BC=?

Mathematics
2 answers:
kow [346]2 years ago
3 0

Answer:

X=5

AB=13

BC=17

Step-by-step explanation:

So first you add the two equations together and the total will have to be 30.

So, 2x+3-4x-3=30

Simplified 6x=30

x=5.

2x+3 -> 5 times 2 + 3

4x - 3 -> 5 times 4 - 3

Brut [27]2 years ago
3 0

Answer:

Step-by-step explanation:

AB + BC = AC

2x +3 + 4x - 3 = 30

2x + 4x + 3 - 3 = 30

Combine like terms

6x = 30

Divide both sides by 6

x = 30/6

x = 5

AB = 2x + 3 = 2*5 + 3 = 10 + 3

AB = 13

BC = 4x - 3 = 4*5 - 3 = 20 - 3

BC = 17

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<h3><u>Answer</u><u>:</u><u>-</u></h3>

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<h3><u>step-by</u><u>-</u><u>step</u><u> </u><u>Explanation</u><u>:</u><u>-</u></h3>

{\boxed{\quad\:\mapsto\rm Firstly\:Let's\:understand\:the\:concept:-}}

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This is a isosceles triangle. As it is a triangle we can apply sum theory. we have to take the sum of given unknown polynomials as 180° .Then by solving it we can find the value of x.

<h3><u>Solution</u><u>:</u><u>-</u></h3>

Given angles

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According to sum theory

{\boxed{\sf The \:sum\:of\:angles=180°}}

  • Substitute the values

\qquad \quad{:}\longmapsto\tt (6x+10)+(x+17)+(4x-34)=180

  • Remove brackets

\qquad \quad{:}\longmapsto\tt 6x+10+x+17+4x-34=180

  • Together like polynomials and constants

\qquad \quad{:}\longmapsto\tt 6x+x+4x+10+17-34=180

\qquad \quad{:}\longmapsto\tt 11x-7=180

  • Interchange sides

\qquad \quad{:}\longmapsto\tt 11x=180+7

\qquad \quad{:}\longmapsto\tt 11x=187

\qquad \quad{:}\longmapsto\tt x=\cancel{\dfrac{187}{11}}

  • Simplify

\qquad \quad{:}\longmapsto\tt x=17

\therefore\sf The \:value\:of\:x\;is\:17.

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