c and e because statistical questions can be answered by collecting data that can have variability.
Answer:
The 90% confidence interval for the mean µ of the population of female runners.
( 65.0328 , 66.5672)
Step-by-step explanation:
<u>Step(i)</u>
Given A sample of 12 runners showed a sample mean height of 65.80 inches and a sample standard deviation of 1.95 inches.
Given sample size is n = 12 <30 so small sample
Given sample mean (x⁻) = 65.80 inches
sample standard deviation (S) = 1.95 inches.
<u>Step(ii)</u>
Assume the population is approximately normal.
The 90% confidence interval for the mean µ of the population of female runners.

substitute all above interval

The degrees of freedom γ=n-1 = 12-1=11
From t- table = 1.363 at 90 % 0r 0.10 level of significance

on calculation , we get
(65.80 -0.7672 ,65.80 + 0.7672)
( 65.0328 , 66.5672)
Answer:
Step-by-step explanation:
we have
5x+6y= -11
5x-2y=-3
we will multiply first equation with -1
-5x-6y=11 and add it with the second
5x-2y=-3
-8y=8
y=-1
we go to our original equation and replace y=-1
5x-6=-11
5x=-11+6
5x=-5
x=-1
Answer:
the limit does not exist
Step-by-step explanation:
As x approaches π/2 from below, tan(x) approaches +∞. A x approaches π/2 from above, tan(x) approaches -∞. These two limits are not the same, so the limit is said not to exist.
___
For a limit to exist, it must be the same regardless of the direction of approach.
Answer:
C. 125
Step-by-step explanation:
Given:
Bacteria on day 1 = 5
On day 2, each bacteria got split into 5.
So, number of bacteria on day 2 = 
Now, again on day 3, each of the 25 bacteria got split into additional 5 bacteria.
So, number of of bacteria on day 3 = 
Therefore, the population of bacteria on day 3 is 125.