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3 years ago

Estimate the sum.

Mathematics

2 answers:

rusak2 [61]3 years ago

8 0

It has to be 10,000
Since the first stays at 1,000 and the second goes to 9,000 so add them to gather and it’s 10,000

castortr0y [4]3 years ago

6 0

1,239 + 8,568= 9,807 but if you round it then it would be 10,000

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How much will the payment be on a 2021 Jeep car costing $29,000 at 3.25 APR Interest on a 72 month loan with no down payment?

Tasya [4]

9514 1404 393

Answer:

$443.87

Step-by-step explanation:

The amortization formula tells you the payment.

A = P(r/12)/(1 -(1 +r/12)^(-12t))

where P is the loan amount at annual rate r for t years.

A = $29,000(0.0325/12)/(1 -(1 +0.0325/12)^(-72)) = $443.87

The monthly payment will be $443.87.

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3 years ago

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Rzqust [24]

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4 years ago

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babunello [35]

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7 0

3 years ago

The segments shown below could form a triangle.<br> O<br> A. True<br> O<br> B. False

lara [203]

Answer:

False

Step-by-step explanation:

5 0

3 years ago

Sample annual salaries (in thousands of dollars) for employees at a company are listed. (a) Find the sample mean and sample s

Helen [10]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

The value is attached in the image file please find it.

In point a:

First, we calculate the find the mean,

Formula:

$\to Mean (\bar{x}) = \frac{( \sum x)}{n}$

$=\frac{540}{13}\\\\ = 41.54$

To calculate the standard deviation, subtract the mean value from all observations then square its value:

$SD = \sqrt{\frac{\sum(x-\bar{x})^2}{n-1}} \\$ $= \sqrt{ \frac{339.2308}{13-1}}$

$= \sqrt{ \frac{339.2308}{12}}\\\\= \sqrt{28.269}\\\\=5.31$

please find attached file

In point b:

New $x_i = 1 x_i + 0.05 x_i = 1.05 x_i$

Calculate new mean:

$\to \bar{x} = \frac{\sum x}{n} \\$

$=\frac{567}{13} \\\\= 43.62$

calculating the standard deviation:

$SD = \sqrt{\frac{\sum(x-\bar{x})^2}{n-1}} \\$ $= \sqrt{ \frac{374.0022}{13-1}}$

$= \sqrt{ \frac{374.0022}{12}}\\\\= \sqrt{31.16}\\\\=5.58$

please find attached file

In point C:

Calculate new mean:

$\to \bar{x} = \frac{\sum x}{n} \\$

$=\frac{47.25}{13} \\\\= 3.46$

calculating the standard deviation:

$SD = \sqrt{\frac{\sum(x-\bar{x})^2}{n-1}} \\$ $= \sqrt{ \frac{2.5975}{13-1}}$

$= \sqrt{ \frac{2.5975}{12}}\\\\= \sqrt{0.216}\\\\=0.46$

please find attached file

In point d:

for b,

New $\bar{x}= 1.05 \bar{x}= 1.05(41.54) =43.62$

New $s= 1.05s= 1.05(5.31)=5.57$

for c,

New $\bar{x}= \frac{ \bar{x}}{12}= \frac{41.54}{12} = 3.46$

New $s = \frac{s}{ 12} = \frac{5.31}{12}= 0.44$

4 0

4 years ago