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3 years ago

each of the four sides of a swimming pool measures 12 meters who is 6 m in feet how much water is needed to fit in completely

Mathematics

2 answers:

Snezhnost [94]3 years ago

6 0

Volume = Length x Width x Height

Volume = 12 x 12 x 6 = 864 m³

Answer: 864 m³

makkiz [27]3 years ago

5 0

I would multiply 12*6 which you get 72m of water

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Simplify the expression 8(2x - 6y + 3) using the distributive property. *

yawa3891 [41]

Answer:

16x - 48y +24

Step-by-step explanation:

We can use the distributive property to expand:

8(2x - 6y + 3)
8 x 2x - 8 x 6y + 8 x 3
16x - 48y + 24

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3 years ago

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Natasha2012 [34]

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3 years ago

Find an equation of the line through the given pair of points. (-7,-5) and (-1,-9) The equation of the line is (Simplify your an

Phantasy [73]

Answer:

The equation of the line is y = -2/3x - 29/3

Step-by-step explanation:

The slope of these points (-7,-5) and (-1,-9) is m = -2/3

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3 years ago

the millers make a 70-mile Thanksgiving trip to visit their grandparents.Pat miller belives driving at a steady rate of 50 miles

blsea [12.9K]

Answer:

Step-by-step explanation:

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3 years ago

An arc measures 50°in a circle with a radius of 8 cm. What is the area of the sector to the nearest tenth of a square centimeter

marysya [2.9K]

Answer:

$27.9cm^2$

Step-by-step explanation:

The <u>total area</u> of the circle is given by:

$a=\pi r^2$

where $\pi$ is a constant $\pi=3.1416$

and $r$ is the radius: $r=8cm$

Thus the total area of this circle is:

$a=(3.1416)(8cm)^2\\a=(3.1416)(64cm^2)\\a=201.06cm^2$

We want only the area of the arc that measures 50°. For this we must remember that the arc of the total circle is 360°.

Thus, we want 50° out of the 360° degrees in the circle. For this, we divide the total area by 360 and then we multiply by 50:

$\frac{201.06cm^2}{360}(50)=0.5585cm^2(50)=27.9cm^2$

the area of the sector to the nearest tenth is $27.9cm^2$

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3 years ago