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ArbitrLikvidat [17]
3 years ago
6

What's the value of given expression :

ula1" title=" \sqrt{8 \times 2} " alt=" \sqrt{8 \times 2} " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Drupady [299]3 years ago
8 0

Answer:

\sqrt{8 \times 2}   \\ =  \sqrt{16}  \\  =  \sqrt{4 \times 4}  = 4 \\ thank \: you

Fed [463]3 years ago
3 0

Answer:

4

Step-by-step explanation:

root 8*2

root 16

4

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What are the potential solutions of In(x^2-25)=0?
Maslowich

Answer:

x =\pm \sqrt{26}

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

<u>Equation</u><u> </u><u>:</u><u>-</u><u> </u>

\implies log_e {(x^2-25)}= 0

<u>In </u><u>general</u><u> </u><u>:</u><u>-</u><u> </u>

  • If we have a logarithmic equation as ,

\implies log_a b = c

Then this can be written as ,

\implies a^c = b

In a similar way we can write the given equation as ,

\implies e^0 = x^2 - 25

  • Now also we know that a^0 = 1 Therefore , the equation becomes ,

\implies 1 = x^2 - 25 \\\\\implies x^2 = 25 + 1 \\\\\implies x^2 = 26 \\\\\implies x =\sqrt{26} \\\\\implies x = \pm \sqrt{ 26}

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6 0
3 years ago
What is the slope of a line with a x-intercept of -3 and a y-intercept of -4?
GuDViN [60]

The x intercept is -3 so the point (-3,0) is on the line. This point is on the horizontal x axis. The x intercept is always in the form (NUMBER,0) where you replace "NUMBER" with any number you want.

The y intercept is -4 so we know that (0,-4) is also on the line. This is on the vertical y axis. The y intercept is always in the form (0,NUMBER)

Use the slope formula to find the slope of the line through the points (-3,0) and (0,-4)

m = (y2-y1)/(x2-x1)

m = (-4-0)/(0-(-3))

m = (-4-0)/(0+3)

m = -4/3

The answer is choice B: -4/3

I have a feeling you mixed up x and y somehow when you got -3/4

6 0
4 years ago
Za and Z6<br> are<br> complementary angles. Za measures 78°.<br> What is the measure of Zb?
VARVARA [1.3K]

Answer:

\boxed{\angle b = 12 \degree}

Given:

\angle a \: and \: \angle b \: are \: complementary \: angles\\ \\ \angle a = 78 \degree

Step-by-step explanation:

Two Angles are Complementary when they add up to 90° (a Right Angle).

=  > \angle a + \angle b = 90 \degree \\  \\  =  >  78 \degree +  \angle b = 90\degree \\  \\  =  > \angle b = 90 \degree - 78 \degree \\  \\  =  >  \angle b = 12 \degree

5 0
3 years ago
The area of a rectangular pool is (x 2 + 17x + 72) square meters. There is a 3-meter-wide concrete
spayn [35]

Step-by-step explanation:

the area is

(x² + 17x + 72) m²

it is the result of the usual

length × width

calculation.

length = x + g

width = x + h

length × width = x² + gx + hx + ab = x² + (g+h)x + gh =

= x² + 17x + 72

g + h = 17

gh = 72

just by looking at it that gives us 9 and 8 as g and h.

FYI - formally to calculate them we can say

g = 17 - h

(17 - h)h = 72

17h - h² = 72

h² - 17h + 72 = 0

the solution to such a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

x = h

a = 1

b = -17

c = 72

h = (17 ± sqrt(17² - 4×1×72))/(2×1) =

= (17 ± sqrt(289 - 288))/2 = (17 ± 1)/2

h1 = (17 + 1)/2 = 18/2 = 9

h2 = (17 - 1)/2 = 16/2 = 8

as we can see

g = 17 - h

if we say h = 9, then g = 8.

if we say h = 8, then g = 9.

so, these are our solutions.

we simply pick that length is longer than width, so, g = 9, h = 8.

the area including the walkway is then

(length + 3)(width + 3) =

= (x + 9 + 3)(x + 8 + 3) = (x + 12)(x + 11) m²

and the dimensions incl. the walkway are

length = x + 9 + 3 = x + 12

width = x + 8 + 3 = x + 11

8 0
2 years ago
Determine the solution of the equation (x-4)=81
Crazy boy [7]

Answer:

Step-by-step explanation:

there is four solutions

1.x = 3

2.x = -3

3. x=  0.0000 - 3.0000

 4.x=  0.0000 + 3.0000

7 0
4 years ago
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