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Evgesh-ka [11]
2 years ago
10

The math 1 test has 20 questions worth a total of 100 points. The test consists of multiple choice questions worth 4 points each

and word problems worth 8 points each
Mathematics
1 answer:
taurus [48]2 years ago
4 0
There would be 15 multiple choice problems and 5 word problems.

15 x 4 = 60

5 x 8 = 40

60 + 40 = 100
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the total cost, c, of an item purchased from a store is c = p .07p, where p is the price before sales tax, and there is a 7% sal
alekssr [168]
C = p + 0.07p
c = p(1 + 0.07)
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3 years ago
1. if csc β = 7/3 and cot β = - 2√10 / 3, Find sec β
slava [35]

Step-by-step explanation:

1.

\tan \beta  =  \frac{1}{ \cot \beta }  =  -  \frac{3}{2 \sqrt{10} }  =  -  \frac{3 \sqrt{10} }{20}

\csc \beta  \tan \beta  =  \frac{1}{ \cos \beta  }  =  \sec \beta

Therefore,

\sec \beta  = ( \frac{7}{3} )( -  \frac{3 \sqrt{10} }{20} ) =  -  \frac{7 \sqrt{10} }{20}

2.

\csc y =  \frac{1}{ \sin y}  =  -  \frac{ \sqrt{6} }{2}

=  >  \sin y =  -  \frac{ \sqrt{6} }{3}

Use the identity

\cos y =   \sqrt{1 -  \sin ^{2} y}    \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \\ =  \sqrt{1 -  {( -  \frac{ \sqrt{6} }{3}) }^{2} }  =  -  \frac{ \sqrt{3} }{3}

We chose the negative value of the cosine because of the condition where cot y > 0. Otherwise, choosing the positive root will yield a negative cotangent value. Now that we know the sine and cosine of y, we can now solve for the tangent:

\tan \beta  =  \frac{ \sin y}{ \cos y} =( -  \frac{ \sqrt{6} }{3} )( -  \frac{3}{ \sqrt{3} } ) =  \sqrt{2}

3. Recall that sec x = 1/cos x, therefore cos x = 5/6. Solving for sin x,

\sin x =   \sqrt{1 -  \cos ^{2} x} =  \sqrt{ \frac{11}{6} }

Solving for tan x:

\tan x =  \frac{ \sin x}{ \cos x}  =  (\frac{ \sqrt{11} }{ \sqrt{6} } )( \frac{6}{5} ) =  \frac{ \sqrt{66} }{5}

5 0
3 years ago
If two similar cones have volumes of 320cm^3 and 1,080cm^3, find the scale factor.
Alexeev081 [22]
The ratio of the volumes is equal to the scale factor cubed.

\frac{V_1}{V_2}=k^3 \\ \\
\frac{320 \ cm^3}{1080 \ cm^3}=k^3 \\
\frac{8}{27}=k^3 \\
k=\sqrt[3]{\frac{8}{27}} \\
\boxed{k=\frac{2}{3}} \Leftarrow \hbox{answer B}
3 0
3 years ago
Write an equivalent ratio for 7:8 with 40 as one of the terms.
kvv77 [185]

Answer:

Step-by-step explanation:

Five equivalent ratios:

7:8  = 14:16

      = 21:24

      = 70:80

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2 years ago
In the process of electricity, what flow through
Natalija [7]
Current (A)

Q=It
where Q is electric charge, I is current and t is time
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2 years ago
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