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UNO [17]
3 years ago
9

Find the size of deb

Mathematics
1 answer:
Akimi4 [234]3 years ago
8 0

Answer:

4x + 3 = 6x - 53 \\ 6x - 4x = 3 + 53 \\ 2x = 56 \\ x =  \frac{56}{2}  = 28

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Please help me with this question
boyakko [2]

Answer:

0.7999989281

Step-by-step explanation:

x1 = cos^-1 (3/5)

x1= 53.13°

sin(53.13) = 0.7999989281

5 0
3 years ago
Identify each coefficient.<br> 1) 8x =<br> 2) 3m =<br> 3) y =<br> 4) 14t =
777dan777 [17]
1)8
2)3
3)1
4)14
the coefficient is the number in front of the variable
6 0
3 years ago
Round 5.951 to the place value of the underlined digit ( underlined digit is 9)
mr Goodwill [35]

Answer:

A.) 6.0

Step-by-step explanation:

I dont explain very well, but..

if the next number is above or it is 5, then u round up

5 0
3 years ago
The triangle below is equilateral. Find the length of side x to the nearest tenth.
Gemiola [76]

Answer:

\sqrt{\frac{15}{2} } or 2.738

Step-by-step explanation:

Let’s just look at the triangle on the top with the \sqrt{10} on the top and x on the bottom. (Basically the top half to the equilateral triangle)

There is a small square in the bottom right corner, which indicates that this triangle is a right triangle. This means that we can use the Pythagorean Theorem: a^{2} +b^{2} =c^{2}

We know that \sqrt{10} is our hypotenuse, and therefore our c in our equation. Let’s say that x=a in our equation. Therefore we are left to find b. However, b is half the length of the side of the original equilateral triangle. An equilateral triangle means that all three sides are the same length. Therefore our side would also be \sqrt{10} units long. However we know that b is half of that value, so b=\frac{1}{2}(\sqrt{10}) or \frac{\sqrt{10} }{2}

Plugging these values into the equation:

x^2+ (\frac{\sqrt{10} }{2})^{2}=\sqrt{10} ^{2}

x^{2}=\sqrt{10} ^{2}-\frac{\sqrt{10} }{2} ^{2}

x^{2} =10-\frac{10}{4}

x^{2} =\frac{15}{2}

x=\sqrt{\frac{15}{2} }

This approximately equals 2.738

5 0
2 years ago
Read 2 more answers
Why does it help to rearrange
hichkok12 [17]

Answer:

You don't really need to do it, but it helps you keep things more organized and easier to follow. Imagine if you're doing some multi-variable equation,

2a + 5b + 4d + 3c + b + a + 2d

that looks like a mess, it'll be easier to look at if you put all the similar variables next to each others like this:

a + 2a + b + 5b + 3c + 2d + 4d

(a + 2a) + (b + 5b) + 3c + (2d + 4d)

now you can add them up much easier.

8 0
3 years ago
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