The measure of ∠B is (3x – 4 )° and the measure of ∠D is (2x – 6)°. What are the measures of angles B and D?

2. Solve for y. A 10.5 B 9 C 13.5 D 12

Vera_Pavlovna [14]

It’s A
Because if you subtract 12 from 96 you’ll get 8y=84 then divide both sides by 8 you get 21/2 simplify and get 10.5 or 10 1/2

5 0

2 years ago

Katie is buying a refrigerator for her apartment. She's choosing between a regular fridge and a gigantic fridge . She notices th

Anuta_ua [19.1K]

Answer:

Volume of the gigantic fridge is 2.5 times the volume of regular fridge.

Step-by-step explanation:

This question is incomplete; here is the complete question.

Katie is buying a refrigerator for her apartment. She's choosing between a regular fridge and a gigantic fridge (details are shown in the table below). She notices that the gigantic fridge costs 3 times as much as the regular fridge.

How many times as great is the volume of the gigantic fridge as the volume of the regular fridge?

Area of the base, Height, Price

Regular Fridge: 1m² / 2m / $200

Large Fridge: 2m² / $\frac{5}{2}$ m / $600

In this question cost of the large fridge is 3 times as much as the regular fridge.

Area of the base of regular fridge = 1m²

Height of the regular fridge = 2m

So volume of this fridge = 1×2 = 2m³

Area of the base of the large fridge = 2m²

Height of the large fridge = $\frac{5}{2}$ m

Volume of the large fridge = $\frac{5\times 2}{2}$ = 5m³

Ratio of the volumes of the large and regular fridge = $\frac{5}{2}=2.5:1$

Therefore, volume of the gigantic fridge is 2.5 times the volume of regular fridge.

3 0

2 years ago

A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win

sveta [45]

Answer:

The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25% of their capacity, how much energy, in kilowatt-hours, can the region's wind farms generate in one year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year

Part B

Given that the average household in the region uses about 10,000 kilowatt-hours of energy each year, how many households can be powered by these wind farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

Amount of households = 4,818'000,000/10,000 = 481,800

8 0

3 years ago

Catherine reads 7 1/2 pages of mystery book in 9 minutes. What is her average reading rate in pages per minute?

ki77a [65]

7 1/2 pages divided by 9 minutes is 5/6 pages per minute.

4 0

3 years ago

What is the value of b in the equation (y)*

KonstantinChe [14]

Answer:

b = -6