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Virty [35]
3 years ago
8

The measure of ∠B is (3x – 4 )° and the measure of ∠D is (2x – 6)°. What are the measures of angles B and D?

Mathematics
2 answers:
andrew11 [14]3 years ago
7 0
B = 110 D = 70 your welcome yall
Nuetrik [128]3 years ago
6 0
B=110, d=70

Hope this helps!
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Nataly [62]

Answer:

The probability of drawing the first pink ball is \frac{3}{10}.

Because you drew that first pink ball, there are two pink balls left and the total number of balls left is nine.

Hence, the probability of drawing another pink ball after drawing the first pink ball would be:

\frac{3}{10} *\frac{2}{9} =\frac{1}{15}

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Conclusions A catalog sales company promises to deliver orders placed on the Internet within 3 days.​ Follow-up calls to a few r
IrinaVladis [17]
It is d

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3 years ago
Amelia recorded the average rainfall amount, in inches, for two cities over the course of a few months.
Ann [662]
City a: 5+4+3+5+5+4+2=28 divided by 7=4. city b:3+6+7+3+8+3=30 divided by 6=5.
B)City a: 4, city b: 1.5.
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6 0
3 years ago
Read 2 more answers
Dill and Bromberg, Problem 1.23. The San Francisco football team plays better in fair weather. They have a 70% chance of winning
shtirl [24]

Answer:

a) 40% probability that San Francisco will win.

b) 80% probability that the weather was bad

Step-by-step explanation:

We have these following probabilities:

60% chance of snow(bad weather).

If there is bad weather, 20% probability of SF winning.

100-60 = 40% chance of good weather.

If there is good weather, 70% probability of SF winning.

(a) If they play in the Super Bowl in Wisconsin and the weatherman predicts a 60% chance of snow that day, what is the probability that San Francisco will win.

20% of 60%, plus 70% of 40%. So

0.2*0.6 + 0.7*0.4 = 0.4

40% probability that San Francisco will win.

(b) Given that San Francisco lost, what is the probability that the weather was bad?

We use the conditional probability formula to solve this question.

Conditional probability:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: SF losing

Event B: Bad weather

P(A)

From a), 40% probability that SF wins. So 100-40 = 60% = 0.6 probability that SF losses.

So P(A) = 0.6

P(A and B)

60% chance of snow. If it snows, 80% probability of SF losing. So

P(A \cap B) = 0.6*0.8 = 0.48

P(B|A) = \frac{0.48}{0.60} = 0.8

80% probability that the weather was bad

6 0
3 years ago
Please help!!
damaskus [11]

Answer:

6a) 1

6b) 11

7a) 4

7b) 10

8a) 6

8b) 14

9a) 11

9b) 13

Step-by-step explanation:

In order to make a triangle, we need to follow this property:

a <= b + c

(Known as "triangle inequality")

Where 'a' is the bigger side and 'b' and 'c' are the other two sides.

So, using this property, we can solve the following problems:

6a) Maximum side will be 6:

6 <= 5 + c

c = 1

6b) Minimum sides will be 5 and 6:

a <= 5 + 6

a = 11

7a) Maximum side will be 7:

7 <= 3 + c

c = 4

7b) Minimum sides will be 3 and 7:

a <= 3 + 7

a = 10

8a) Maximum side will be 10:

10 <= 4 + c

c = 6

8b) Minimum sides will be 4 and 10:

a <= 4 + 10

a = 14

9a) Maximum side will be 12:

12 <= 1 + c

c = 11

9b) Minimum sides will be 1 and 12:

a <= 1 + 12

a = 13

7 0
3 years ago
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