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sertanlavr [38]
2 years ago
11

Find the missing side of each triangle.

Mathematics
2 answers:
Arisa [49]2 years ago
7 0

By using Pythagoras theorem :

  • {x}^{2}   = (12.7) {}^{2}   - (5.5)x {}^{2}

  • {x}^{2}  = 161.29 - 30.25

  • {x}^{2}  =131.04

  • x =  \sqrt{131.04}

  • x = 11.4

Correct choice is B

xxTIMURxx [149]2 years ago
4 0

Answer:

The choice B) 11.4

Step-by-step explanation:

{x}^{2}  +  {(5.5)}^{2}  =  {(12.7)}^{2}  \\  {x}^{2}  + 30.25 = 161.29 \\  {x}^{2}  = 13104 \\ x = 11.4

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apex if you put down 15% on a $9000 car and pay monthly payments of $189.40 for 48 months what is the total price of the car
defon

The total amount payable for the car if you put a down 15% on a $9000 car and payment of $189.40 for 48 months will be:

Amount=(15/100×9000)+(189.40×48)

=1350+9091.2

=10,441.2

The total amount of money paid for the car after a period of time will be $10,441.2



6 0
3 years ago
This is gonna be a 30 0oint question so if you can solve it
USPshnik [31]

Answer:

y = 36

Step-by-step explanation:

Everything in x-column is multiplied by 2, so everything in y-column is divided by 2 as per the inverse function.

=> 72/2

=> 36

5 0
2 years ago
Quadrilateral ABCD undergoes a reflection across the x-axis to form quadrilateral A'B'C'D'. The coordinates of A' are ( , ).
natka813 [3]
1) A(-5,-3); B(-6,-1); C(-3,-1) ; D(-2,-3)

When a refection is done about x-axis, the values of the abscise x remain identical & the value of ordinate  just change their signs:
A(-5,-3); A'(-5,+3)
B(-6,-1); B'(-6,+1)
C(-3,-1); C'(-3,+1)
D(-2,-3); D'(-2,+3)

2) A'B'C'D' is translated 3 UNITS RIGHT, that means the ordinated of A'B'C'D'
are the same but the abscises have been increased by 3 UNITS ;

A'(-5,+3) ==>A"(-2,3)
B'(-6,+1) ==>B"(-3,1)
C'(-3,+1) ==>C"(0,1)
D'(-2,+3) ==>D"(1,3)
5 0
3 years ago
Read 2 more answers
The total area of the figure below is (blank) units look at picture to solve
Tpy6a [65]
9x4=36 squared units
3 0
3 years ago
Three siblings- Kate, Sarah, and Dave- committed themselves to volunteer 160 hours for a homeless charity to build new housing .
liraira [26]

Kate worked for 50 hours, Dave worked for 65 hours and Sarah

worked for 45 hours

Step-by-step explanation:

Three siblings- Kate, Sarah, and Dave- committed themselves to

volunteer 160 hours for a homeless charity to build new housing

1. Dave worked 15 hours more than Kate

2. Sarah worked 5 hours fewer than Kate

3. The total hours for them is 160 hours

Assume that Kate worked for x hours

∵ Kate worked for x hours

∵ Dave worked 15 hours more than Kate

∴ Dave worked for x + 15 hours

∵ Sarah worked 5 hours fewer than Kate

∴ Sarah worked x - 5 hours

∵ They worked for 160 hours

- Add the number of worked hours of them and equate the sum

  by 160

∴ x + x + 15 + x - 5 = 160

- Add like terms in the left hand side

∴ 3x + 10 = 160

- Subtract 10 from both sides

∴ 3x = 150

- Divide both sides by 3

∴ x = 50 hours

∵ Kate worked for x hours

∴ Kate worked for 50 hours

∵ Dave worked for x + 15 hours

∴ Dave worked for 50 + 15 = 65 hours

∵ Sarah worked for x - 5 hours

∴ Sarah worked for 50 - 5 = 45 hours

Kate worked for 50 hours, Dave worked for 65 hours and Sarah

worked for 45 hours

Learn more:

You can learn more about equation in brainly.com/question/11229113

#LearnwithBrainly

6 0
3 years ago
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