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3 years ago

Heres the answer l.m.a.o

Mathematics

2 answers:

Ymorist [56]3 years ago

5 0

Love that . Perfect answer

torisob [31]3 years ago

4 0

Answer:

That's a solid answer there.

Step-by-step explanation:

LOL

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People travel by bus or by train from hiraddug station on tuesday 420 people travelled by bus from the station the ratio of the

goldenfox [79]

The number of people travelled by train from the station on tuesday is 357.

Let us assume the number of people who travelled by train from the station on tuesday be x. Using the concept of ratio and proportion to solve and calculate x.

Forming the ratio-

20 : 17 = 420 : x

Solving the ratio and proportion for the value of x

x = (420 × 17) ÷ 20

Performing multiplication in numerator

x = 7140 ÷ 20

Performing division on Right Hand Side of the equation

x = 357

Therefore, based on the information, 357 people used to travel.

Learn more about ratio and proportion -

brainly.com/question/12024093

#SPJ4

3 0

1 year ago

Geometry help plz will mark brainliest.

Alex17521 [72]

I think it's 12x.
I'm not a 100% sure though, but I hope this helps. =^D

5 0

3 years ago

Can anyone help me with this math stuff? :p

Mars2501 [29]

Answer:

if the recipe makes 48 cookies and the serving size is 3 then you should actually can just make the regular recipe and have 9 cookies leftover

Step-by-step explanation:

7 0

3 years ago

A sprinter who weighs 706 N runs the first 5.5 m of a race in 1.6 s, starting from rest and accelerating uniformly. What are the

zhenek [66]

Answer:

(a) Speed = 6.875 m/s

(b) Kinetic Energy = 1.70 kJ

Step-by-step explanation:

Given:

d = 5.5 m

t = 1.6 s

W = 706 N

Part (a)

Using the equation of motion with the assumption of zero initial speed:

$d = \frac{1}{2} ({v-0})t$

$5.5= \frac{1}{2} (1.6v)$

The speed of the sprinter then become:

$v = 6.875 m/s$

Part (b)

Convert the weight of the sprinter to mass:

$m = \frac{w}{g}$

$m = \frac{706}{9.8}$

$m = 72 kg$

KE (Kinetic Energy) can then be calculated as:

$KE = \frac{1}{2} mv^{2}$

$KE = \frac{1}{2} (72)(6.875)^{2}$

$KE = 1701.56 J = 1.70 kJ$

Part (c)

The change of the kinetic energy is equivalent to the work done by the sprinter. The average power P is the rate of the work done and can be calculated as

$P = \frac{KE}{t} \\\$