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2 years ago

Please answer all 4 questions:)

Mathematics

2 answers:

liberstina [14]2 years ago

8 0

The mass is 64204832(

Scorpion4ik [409]2 years ago

3 0

Answer:

1. d=m/v

=57.6/112.9

=0.51018601

=0.510g/cm³(3s.f.)

2. m=d×v

=1.8×54

=97.2g

3. v=m/d

=63.8/12.7

=5.02362205

=5.02cm³(3s.f.)

4. v=length×breath×height

=12×2×6

=144m³

216g=0.216kg

d=m/v

=0.216/144

=0.0015kg/m³

Step-by-step explanation:

density=mass/volume

mass=density×volume

volume=mass/density

*make sure the units are correctly placed.

*g/cm³, kg/m³

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X-y=3 in slope intercept form and find x and y intercepts

Dominik [7]

Answer:

x intercept is x=3

y intercept is y=-3

Step-by-step explanation:

We can write this equation in a simpler way to find the values needed. Lets do it. Take:

x-y=3

And sum y in both sides, as we know the equality will maintain:

x-y+y=3+y

x = 3+ y

Now subtract 3 in both sides:

x-3 = y+3-3

x-3=y

So, we can rewrite our equation as y=x-3

The x intercept is a value of x such that the equation in equal to zero; in other words, is the value of x when y is zero. It is also called a zero root. Graphically, its the x value when the function passes trough the x-axis. Lets find if, we nned that:

x-3 = 0

If we sum 3 in both sides:

x-3+3=3

x=3

So, x=3 is x intercept

For finding the y intercept we need the value of y when x is zero. Graphically, is the value of y obtained when the function passes trough the y-axis. So, replace x with 0:

0-3=y

y=-3

Another way to get it is knowing that the y intercept in a polynomial is always the independent term, the one that has no x or y, which in this case is -3.

7 0

2 years ago

If y varies directly as x^2 find k when x=2 and y=8

Grace [21]

I think the answer is 2

8 0

3 years ago

Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are locat

eimsori [14]

Answer:

There are NO real roots for this equation. The only roots have imaginary parts and therefore cannot be represented on the real x-axis.

Step-by-step explanation:

We notice that the expression on the left of the equation is a quadratic with leading term $2x^2$ , which means that its graph is that of a parabola with branches going up.

Therefore, there can be three different situations:

1) if its vertex is ON the x axis, there would be one unique real solution (root) to the equation.

2) if its vertex is below the x-axis, the parabola's branches are forced to cross it at two locations, giving then two real solutions (roots) to the equation.

3) if its vertex is above the x-axis, it will have NO real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently.

We recall that the x-position of the vertex for a quadratic function of the form $f(x)=ax^2+bx+c$ is given by the expression:

$x_v=\frac{-b}{2a}$

Since in our case $a=2$ and $b=-3$ , we get that the x-position of the vertex is:

$x_v=\frac{-b}{2a}\\x_v=\frac{-(-3)}{2(2)}\\x_v=\frac{3}{4}$

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = 3/4:

$y_v=f(\frac{3}{4})=2( \frac{3}{4})^2-3(\frac{3}{4})+4\\f(\frac{3}{4})=2( \frac{9}{16})-\frac{9}{4}+4\\f(\frac{3}{4})=\frac{9}{8}-\frac{9}{4}+4\\f(\frac{3}{4})=\frac{9}{8}-\frac{18}{8}+\frac{32}{8}\\f(\frac{3}{4})=\frac{23}{8}$

This is a positive value for y, therefore we are in the situation where there is NO x-axis crossing of the parabola's graph, and therefore no real roots.

We can though estimate a few more points of the parabola's graph in order to complete the graph as requested in the problem. For such we select a couple of x-values to the right of the vertex, and a couple to the right so we can draw the branches. For example: x = 1, and x = 2 to the right; and x = 0 and x = -1 to the left of the vertex:

$f(-1) = 2(-1)^2-3(-1)+4= 2+3+4=9\\f(0)=2(0)^2-3(0)+4=0+0+4=4\\f(1)=2(1)^2-3(-1)+4=2-3+4=3\\f(2)=2(2)^2-3(2)+4=8-6+4=6$