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marysya [2.9K]
2 years ago
5

Solve for x ... please help

Mathematics
1 answer:
Mrac [35]2 years ago
5 0

Answer:

7x + 49 \degree = 2x + 94\degree \\ 7x - 2x = 94\degree - 49 \degree \\ 5x = 45\degree \\ x =  \frac{45}{5}  \\ x = 9 \\ check \\ 7(9) + 49 = 112\degree \\ 2(9) + 94 = 112\degree

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Please help meeh thank u thank u
Sunny_sXe [5.5K]

Answer:

The location would be between 4 and 5.

Step-by-step explanation:

The square root of 19 would be around 4.3. So you would put a mark between the two lines that are in between the 4 and 5.

5 0
3 years ago
Sue initially has 5 hours of pop music and 4 hours of classical music in her collection. Every month onwards, the hours of pop m
Snezhnost [94]
<h2>Answer</h2>

f(x) = 5(1.25)x + 4

<h2>Explanation</h2>

To solve this, we are going to use the standard exponential equation:

f(x)=a(1+b)^x

where

a is the initial amount

b is the growth rate in decimal form

x is the time (in months for our case)

Since the hours of classic music remain constant, we just need to add them at the end. We know form our problem that Sue initially has 5 hours of pop, so a=5; we also know that every month onward, the hours of pop music in her collection is 25% more than what she had the previous month, so b=\frac{25}{100} =0.25. Now let's replace the values in our function:

f(x)=a(1+b)^x

f(x)=5(1+0.25)^x

f(x)=5(1.25)^x

Now we can add the hours of classical music to complete our function:

f(x)=5(1.25)^x+5

6 0
3 years ago
Read 2 more answers
Why are points connected in a line graph but not in a bar graph?
BabaBlast [244]
The answer is a line graph  
8 0
3 years ago
Todd and Joan each generate a random sample of the 250 students in Grade 7 at their school. Each sample has 20 students. Todd an
Sloan [31]

Answer:

B. There is a slightly more even distribution in the numbers in​ Joan's Group than in​ Todd's Group. C. Only one​ number, 28, is the same between the two samples.

Step-by-step explanation:Your welcome loves :)

8 0
3 years ago
The J.O. Supplies Company buys calculators from a non-US supplier. The probability of a defective calculator is 10 percent. If 3
RSB [31]

Answer:

There is a 24.3% probability that one of the calculators will be defective.

Step-by-step explanation:

For each calculator, there are only two possible outcomes. Either it is defective, or it is not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability of a defective calculator is 10 percent.

This means that p = 0.1

If 3 calculators are selected at random, what is the probability that one of the calculators will be defective

This is P(X = 1) when n = 3. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{3,1}.(0.1)^{3}.(0.9)^{2} = 0.243

There is a 24.3% probability that one of the calculators will be defective.

3 0
3 years ago
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