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djyliett [7]
3 years ago
13

(-5, -3) and (-5 -6)

Mathematics
2 answers:
Vikki [24]3 years ago
6 0
Are coordinates on a graph
motikmotik3 years ago
5 0
I graphed the slope for you hoped that’s what you asked for because you weren’t very specific

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Find the solutions of the quadratic equation - 2^2+ 3x – 3 = 0
Assoli18 [71]

Answer:

-1/3

Step-by-step explanation:

2^2 + 3x - 3 = 0

4 - 3 + 3x = 0

1 + 3x = 0

x = -1/3

Hope it helps

7 0
2 years ago
The larger nail is a dilation of the smaller nail.
Sergeeva-Olga [200]

Answer: the scale factor is 3/4

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
D/dx (5x4) - (2x³) - (x²)
My name is Ann [436]
\bf y=5x^4-2x^3-x^2\implies \cfrac{dy}{dx}=20x^3-6x^2-2
5 0
3 years ago
Let f(x) = x^3-3x^2+2 and g(x) = x^2 -6x+11 Enter the value of x such that f(x)=g(x)
Licemer1 [7]

The value of x such that f(x) = g(x) is x = 3

<h3>Quadratic equation</h3>

Given the following expressions as shown

f(x) = x^3-3x^2+2 and;

g(x) = x^2 -6x+11

Equate the expressions

x^3-3x^2+2 = x^2 -6x+11

Equate to zero

x^3-3x^2-x^2+2-11 = 0

x^3-3x^2-x^2 + 6x - 9 = 0

x^3-4x^2+6x-9 = 0

Factorize

On factorizing the value of x = 3

Hence the value of x such that f(x) = g(x) is x = 3

Learn more on polynomial here: brainly.com/question/2833285

#SPJ1

7 0
2 years ago
Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation: 22, 18, 1
BigorU [14]

Answer:

a:  Sample mean: 20, Sample standard deviation: 1.732

b:  19.13 <µ < 20.87

c:  18.84< µ < 21.16

d:  as the confidence level increases, the interval becomes wider

Step-by-step explanation:

a:  Sample mean is found by adding up all the individual values of the sample, then dividing by the total number of values in the sample.  

Sample standard deviation is the square root of the variance

See the first attached photo for the calculations of these values.

We need to create a 80% confidence interval for the population.  Since n < 30, we will use a t-value with degree of freedom of 7 (the degree of freedom is always one less than the sample size.  

Look for the column on the t-distribution chart that has "area in two tails" of 0.20 (80%), and row 7 (degree of freedom)

The t-value is 1.415

See the second attached photo for the construction of the confidence interval

We need to create a 90% confidence interval for the population.  Since n < 30, we will use a t-value with degree of freedom of 7 (the degree of freedom is always one less than the sample size.  

Look for the column on the t-distribution chart that has "area in two tails" of 0.10 (90%), and row 7 (degree of freedom)

The t-value is 1.895

See the third attached photo for the construction of the confidence interval

3 0
3 years ago
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