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Ilia_Sergeevich [38]
3 years ago
7

Minutes used (per month)

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
4 0

Answer:

plan B

Step-by-step explanation:

because its more especificated and will be a better answer

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In a certain Algebra 2 class of 28 students, 11 of them play basketball and 13 of them play baseball. There are 11 students who
leonid [27]

Probability of a student playing both basketball and baseball is 7/28

Step-by-step explanation:

Step 1:

It is given the class has 28 students out of which 11 play basketball and 13 play baseball. It is also given that 11 students play neither sport.

Total number of students = 28

Students playing neither sport = 11

Students playing at least one sport = 28 - 11 = 17

Step 2:

Let N(Basketball) denote the number of students playing  basketball and N(Baseball) denote the number of people playing  baseball.

Then N(Basketball U Baseball) denotes the total number of students playing basketball and baseball and N(Basketball ∩ Baseball) denotes playing both basketball and baseball.

Since the number of students playing at least one sport is 17, N (Basketball U Baseball) = 17.

N (Basketball U Baseball) = N(Basketball) + N(Baseball) - N(Basketball ∩ Baseball)

N(Basketball ∩ Baseball) = N(Basketball) + N(Baseball) - N (Basketball U Baseball)

N(Basketball ∩ Baseball) = 11 + 13 - 17 = 7

Step 3:

Number of students playing both basketball and baseball = 7

Total number of students = 28

Probability of a student playing both basketball and baseball is 7/28

Step 4:

Answer:

Probability of a student playing both basketball and baseball is 7/28

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2. In leasing a car, the amount that does not affect the total cost is the PRINCIPAL CHARGE, and the answer for this is option A. 
Hope this helps.</span>
3 0
3 years ago
Read 2 more answers
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