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2 years ago

Please help me with this question :)

Mathematics

1 answer:

Gre4nikov [31]2 years ago

6 0

Let me change this equation up a bit...
x - 4y = -16....same as ur equation in the problem...just a different form

now its just a matter of subbing
when y = 5
x - 4(5) = -16
x - 20 = -16
x = -16 + 20
x = 4
so the first space on ur table above the 5 is 4

no need to go further...answer B

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Answer:

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» Collect second degree terms (x² coefficients) together and first degree terms (x coefficients) and constants

$= { \tt{( - 2 - 1) {x}^{2} + (3 + 1)x + 4 }} \\ = { \boxed{ \tt{ \: - {3x}^{2} + 4x + 4}}}$

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a person with typical deductions earning $75,000 per year would have saved 2% of their income plus $850 in federal taxes. How mu

AURORKA [14]

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3 years ago

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If an airplane’s speed is 850 miles/hour ? What is it’s speed in meters/seconds

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Answer:

379.984 meters per second.

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3 years ago

Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ti

spayn [35]

Answer:

(a) $D(x)=-2,500x+60,000$

(b) $R(x)=60,000x-2500x^2$

(d)Optimal ticket price: $12

Maximum Revenue:$360,000

Step-by-step explanation:

The stadium holds up to 50,000 spectators.

When ticket prices were set at $12, the average attendance was 30,000.

When the ticket prices were on sale for $10, the average attendance was 35,000.

(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)

Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).

$\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500$

Therefore, we have:

$y=-2500x+b$

At point (12,30000)

$30000=-2500(12)+b\\b=30000+30000\\b=60000$

Therefore:

$D(x)=-2,500x+60,000$

(b)Revenue

$R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2$

(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.

$R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12$

The critical value of R(x) is x=12.

(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]

Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.

$R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0$

Therefore:

Optimal ticket price:$12
Maximum Revenue:$360,000

3 0

3 years ago

Mama's Italian Restaurant has collected data about customer sauce orders. It calculated that P(marinara) = 0.82, P(alfredo) = 0.

Keith_Richards [23]

P ( m ) = 0.82
P ( a ) = 0.76
P ( m or a ) = 0.96
P ( m and a ) = ?
--------------------------
P ( m or a ) = P ( m ) + P ( a ) - P ( m and a )
P ( m and a ) = P ( m ) + P ( a ) - P ( m or a ) =
= 0.82 + 0.76 - 0.96 = 0.62
Answer: P ( marinara and alfredo ) = 0.62

7 0

3 years ago