10 L of 30 % saline solution can be formed by mixing 4 L of 60 % saline solution and 6 L of 10 % saline solution.
Step-by-step explanation:
Let x be the number of liters of 60% saline solution
Now we require 10 L of 30% saline solution.
Liter soln % liters saline %
30 % 10 0.3
60 % x 0.6
10 % 10-x 0.1
Now forming the algebraic equation,
0.6x + 0.1 (10-x) = 10 (0.3)
0.6x + 1 - 0.1 x = 3
0.5 x = 2
x = 4 ( 4 l of 60 % solution is required. So 10 % saline solution required is 10 - 4 = 6 L).
Hence, 10 L of 30 % saline solution can be formed by mixing 4 L of 60 % saline solution and 6 L of 10 % saline solution.
<span>The car will stop in 140.625 ft
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Answer:
B
Step-by-step explanation:0
The negative in front of the -(4/5), means you have to move four spaces back but move five up
hopes this helps~
Answer is 9
Step by step explanation
As CB is radius CB=3, CA=3+7=10
X^2=(7+3)^2-3^2=100-9=81
X=9
The answer is 1/2 cuz of simplyfing
