Your answer is T=36. Hope it helps you!
Answer:
Part a) The inequality that represent the situation is
Part b) The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to
Step-by-step explanation:
Let
x------> the length of the first wire
3x---> the length of the second wire
2(3x)=6x -----> the length of the third wire
Part a) WRITE AN *INEQUALITY* THAT MODELS THE SITUATION
we know that
The inequality that represent the situation is
Part b) WHAT ARE THE POSSIBLE LENGTHS OF THE SHORTEST PIECE OF WIRE?
we know that
The shortest piece of wire is the first wire
so
Solve the inequality
Divide by 10 both sides
The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to
Answer: Base=4cm^2
Step-by-step explanation: Area=Base*Height. We know the area is 20 and the height is 5.
20=Base*5. 4*5=20, therefore, the base is 5.
What is your last question?
Answer:
1st, 2nd and 6th options
Step-by-step explanation:
Given
- x + = 6x ( multiply through by 6 to clear the fractions )
4 - 6x + 1 = 36x ← option 1 will have the same solution set
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Adding the 2 fractions on the left side gives
+ - x = 6x , that is
- x = 6x ← option 2 will have the same solution set
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From
4 - 6x + 1 = 36x ( add 6x to both sides )
5 = 42x ← option 6 will have the same solution set