Only twice 3, 11 are only ones
<h3>
Answer: -6/5</h3>
Explanation:
The blue diagonal line goes through the two points (0,2) and (5,-4). These are shown as the dark blue enlarged points. You can pick any other points you want that are on the diagonal line, though these are the easiest as they stand out the most.
Use the slope formula to find the slope through these points
m = (y2-y1)/(x2-x1)
m = (-4-2)/(5-0)
m = (-6)/(5)
m = -6/5
The negative slope means the line goes downhill as you move from left to right along the diagonal line.
To solve this problem, I am going to use the substitution method. To do this, we use our first equation given (s=4r-1) and substitute this given value for s (4r-1) and substitute it into the second equation so that we have an equation with only one variable. This is modeled below:
s = 4r - 1
6r - 5s = -23
6r - 5(4r-1) = -23
Now, we can solve this equation as we would any other equation, using the order of operations outlined by PEMDAS. To begin, we will distribute the factor of -5 through the parentheses on the left side of the equation.
6r - 20r + 5 = -23
Next, we should combine like terms on the left side of the equation:
-14r + 5 = -23
Next, we should subtract 5 from both sides of the equation to get the variable term alone on the the left side of the equation. We get:
-14r = -28
Finally, we should divide both sides by -14 to get the variable r alone on the left side of the equation.
r = 2
Now that we know that value for the variable r, we can substitute this value into one of our original equations (either one will work, but I am choosing to use the first one):
s = 4r - 1
s = 4(2) - 1
Now, we can find the value for s by using multiplication and then subtraction to simplify the right side of the equation.
s = 8-1
s = 7
Therefore, your answer is s = 7 and r = 2.
Hope this helps!
Answer:
ANSWER:
An exponential growth function has constant doubling time.
Step-by-step explanation:
EXPLANATION:
The formula for calculating exponential growth is
A=A'e^kt
here:
A=amount after growth
A'=initial value
e=2.718
k=continuous growth rate
t=time passed
300,000 or three hundred- thousand. :)
