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3 years ago

Reflect the shape against the line x=4

Mathematics

1 answer:

OLga [1]3 years ago

6 0

Answer: Reflect accross the gradient x=4

Step-by-step explanation: Make sure one of the lines or whatever you are drawing is touching or passing thorugh the gradient x = 4

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write the equation of a line in slope intercept form that is parallel to the line x+5y=10 and goes through the point (-5,6)

lilavasa [31]

Answer:

The equation would be y = -1/5x + 5

Step-by-step explanation:

To find the equation of this new line, we first need to identify the slope of the first line. We do this by putting it into slope intercept form.

x + 5y = 10

5y = -x + 10

y = -1/5x + 2

In slope-intercept form, the slope is always the coefficient of x. This makes the slope of the first equation -1/5. Since parallel lines have the same slope, our new slope will also be -1/5.

Given that and the point, we can solve for the equation using point-slope form.

y - y1 = m(x - x1)

y - 6 = -1/5(x + 5)

y - 6 = -1/5x - 1

y = -1/5x + 5

4 0

4 years ago

REPOST!!!!!!! 15 POINTS!!!!!!!

yan [13]

Answer:

m<ACB=1/2 of m<AOB

so m<ACB=45⁰÷2

m<ACB=22.5⁰

I HOPE IT HELPS HAVE NICE DAY!

3 0

3 years ago

Read 2 more answers

Find all solutions of the equation. 5 sin x − 82√ = 3 sin x − 72√

Andrei [34K]

Answer:

x = arcsin(√20.5 -3√2) +2kπ . . . k any integer
x = π - arcsin(√20.5 -3√2) +2kπ . . . k any integer

Step-by-step explanation:

Add √(82) -3sin(x) to both sides to get ...

2sin(x) = √82 -√72

Now, divide by 2 and find the arcsine:

sin(x) = (√82 -√72)/2

x = arcsin((√82 -√72)/2)

Of course, the supplement of this angle is also a solution, along with all the aliases of these angles.

___

In degrees, the solutions are approximately 16.562° and 163.438° and integer multiples of 360° added to these.

6 0

4 years ago

Write the equation of the line passing through the point (−2, 1) that is parallel to y=−4x+3.

Roman55 [17]

Answer:

y = -4x - 7

Step-by-step explanation:

y = mx + b

parallel lines have the same slope m, which in this case is -4

y = -4x + b

now plug in the desired included point to find the y intercept

1 = -4(-2) + b

1 = 8 + b

b = -7

5 0

3 years ago

Pls help quick i need this

irina [24]

Answer:

See explanation

Step-by-step explanation:

Q1-5.

1. Plane parallel to WXT is ZYU.

2. Segments parallel to $\overline {VU}$ are $\overline {ZY}, \overline {WX}$ and $\overline {ST}$

3. Segments parallel to $\overline {SW}$ are $\overline {VZ}, \overline {YU}$ and $\overline {XT}$

4. Segments skew to $\overline {}$ $\overline {XY}$ are $\overline {SV}$ and $\overline {VZ}$ (not lie in the same plane and not parallel)

5. Segments skew to $\overline {}$ $\overline {VZ}$ are $\overline {WX}$ and $\overline {XT}$ (not lie in the same plane and not parallel)

Q6.

a. $\angle 4$ and $\angle 10$ are the same-side interior angles, transversal k

b. $\angle 8$ and $\angle 11$ are alternate exterior angles, transversal m

c. $\angle 1$ and $\angle 4$ do not form any pair of angles

d. $\angle 2$ and $\angle 12$ are the same-side exterior angles, transversal k

e. $\angle 5$ and $\angle 7$ are corresponding angles, transversal j

f. $\angle 2$ and $\angle 13$ are alternate interior angles, transversal l

Q7.

$m\angle 1=m\angle 7=131^{\circ}$ (as vertical angle with angle 7)

$m\angle 2=180^{\circ}-131^{\circ}=49^{\circ}$ (as supplementary angle with angle 1)

$m\angle 8=49^{\circ}$ (as vertical angle with angle 2)

$m\angle 3=m\angle 1=131^{\circ}$ (as corresponding angles when parallel lines p and q are cut by transversal r)

$m\angle 4=m\angle 2=49^{\circ}$ (as corresponding angles when parallel lines p and q are cut by transversal r)

$m\angle 5=m\angle 7=131^{\circ}$ (as corresponding angles when parallel lines p and q are cut by transversal r)

$m\angle 6=m\angle 8=49^{\circ}$ (as corresponding angles when parallel lines p and q are cut by transversal r)

$m\angle 10=m\angle 16=88^{\circ}$ (as vertical angle with angle 16)

$m\angle 9=180^{\circ}-88^{\circ}=92^{\circ}$ (as supplementary angle with angle 16)

$m\angle 15=92^{\circ}$ (as vertical angle with angle 9)

$m\angle 14=m\angle 16=88^{\circ}$ (as corresponding angles when parallel lines p and q are cut by transversal s)

$m\angle 13=m\angle 15=92^{\circ}$ (as corresponding angles when parallel lines p and q are cut by transversal s)

$m\angle 12=m\angle 10=88^{\circ}$ (as corresponding angles when parallel lines p and q are cut by transversal s)

$m\angle 11=m\angle 9=92^{\circ}$ (as corresponding angles when parallel lines p and q are cut by transversal s)

Q8.

$m\angle 7=m\angle 9=105^{\circ}$ (as vertical angles)

$m\angle 8=180^{\circ}-105^{\circ}=75^{\circ}$ (as supplementary angle with angle 9)

$m\angle 10=m\angle 8=75^{\circ}$ (as vertical angles)

$m\angle 6=m\angle 8=75^{\circ}$ (as alternate interior angles when parallel lines a and b are cut by transversal c)

$m\angle 1=180^{\circ}-75^{\circ}-63^{\circ}=42^{\circ}$ (by angle addition postulate)

$m\angle 3=180^{\circ}-42^{\circ}-63^{\circ}=75^{\circ}$ (by angle addition postulate)

$m\angle 4=m\angle 1=42^{\circ}$ (as vertical angles)

$m\angle 5=m\angle 2=63^{\circ}$ (as vertical angles)

$m\angle 11=m\angle 4=42^{\circ}$ (as alternate interior angles when parallel lines a and b are cut by transversal d)

$m\angle 12=180^{\circ}-42^{\circ}=138^{\circ}$ (as supplementary angles)

$m\angle 13=m\angle 11=42^{\circ}$ (as vertical angles)

$m\angle 14=m\angle 12=138^{\circ}$ (as vertical angles)

3 0

3 years ago