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3 years ago

Reflect the shape against the line x=4

Mathematics

1 answer:

OLga [1]3 years ago

6 0

Answer: Reflect accross the gradient x=4

Step-by-step explanation: Make sure one of the lines or whatever you are drawing is touching or passing thorugh the gradient x = 4

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A cylindrical tank that holds 375 L of water is completely full. A pump removes water at a rate of 0.6 L/s. For how many minutes

Misha Larkins [42]

375L-240L=135L
135÷0.6=81
The pump must work for 81 min or 1hr and 21 min until the tank reaches 240L

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3 years ago

1. As part of a survey, 50 students were asked about their favorite lunch item. The results are shown in the table below .The ca

Fiesta28 [93]

1.
A. This statement is wrong because the prediction is valid, not valid.
B. Refer to A.
C.This statement is valid, yet explains the prediction incorrectly.
[D.] This statement is correct because 50 x 6 = 300, therefore 20% of 300 is 60.

2.

A. This is incorrect because it equals 125%
B. This is also incorrect, it equals 12.5%
C. Refer to B
[D.] This is correct, it equals 1.14%, which is less than 1.25%

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4 years ago

What is the difference between csc and arcsin

Korolek [52]

Arcsin is the inverse function of sine, it switches the sine function (reverses it)
cosec is the reciprocal of sine

3 0

3 years ago

If sine ⁡theta equals negative 8/17 and the terminal side of theta lies in quadrant IV, find cosine ⁡ theta .

Lelechka [254]

$\sin^2\theta+\cos^2\theta=1\implies \cos\theta=\pm\sqrt{1-\sin^2\theta}$

Since $\sin\theta=-\dfrac8{17}$ , it follows that

$\cos\theta=\pm\sqrt{1-\dfrac{64}{289}}=\pm\sqrt{\dfrac{225}{289}}=\pm\dfrac{15}{17}$

where the sign depends on the location of the terminal side of the angle. Since the terminal side lies in the fourth quadrant, that means the cosine of the angle is positive, so

$\cos\theta=\dfrac{15}{17}$

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4 years ago

Factor each polynomial x^2-9x+10 <br> Show your work

jok3333 [9.3K]

Answer:

not factorable

Step-by-step explanation:

$x^{2} - 9x +10\\$

The easiest way to factor is to find two numbers of the "a" value (the coefficient before $x^{2}$ ) and the factors of the c value (10) that ADD up to give you -9, in this case it would be:

1 -10 --> 1(-10) gives you -10

1 -1 --> 1(-1) gives you -1

adding these together -10 + (-1) = -11 which does not equal -9.

You could stop here and conclude that this is not factorable by inspection.

Another method: using the quadratic formula to find its roots.

Roots: $(\frac{9-\sqrt{41} }{2}, 0)$ and $(\frac{9+\sqrt{41}}{2}, 0)$

7 0

3 years ago