Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
The best approximation for the solution to this system of equations is (-2.2,-3)
Option C is correct.
Step-by-step explanation:
Solving the system of equations to get the exact value of x:
Let
Putting value of y from eq(1) into eq(2)
So, Value of x is -2.2
The best approximation for the solution to this system of equations is:
x=-2.2 and y = -3
(-2.2,-3)
Option C is correct.
Keywords: System of equations
Learn more about system of equations at:
#learnwithBrainly
The answer is 60. You can find this out by finding the least common multiple of 10 and 12, which is 60 because 10x6=60 and 12x5=60. Hope this helps :)
D. Intersecting lines and lines that have the same equation.
Hope this helps :)
