All categories

3 years ago

Pls help i need this done asap.

Mathematics

2 answers:

Shkiper50 [21]3 years ago

8 0

Answer:

3....................

zaharov [31]3 years ago

4 0

Hey! Darlus would need to get 3 correct answers to bring his score back up to a 0.

You might be interested in

3⁵.2⁴.2¹.3⁶.(3²)⁴ and down (2³)².3⁶<br>

BARSIC [14]

Answer:

$\dfrac{3^{13}}{2}$

Step-by-step explanation:

Given expression:

$\dfrac{3^5 \cdot 2^4 \cdot 2^1 \cdot 3^6 \cdot (3^2)^4}{(2^3)^2 \cdot 3^6}$

$\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:$

$\implies \dfrac{3^5 \cdot 2^4 \cdot 2^1 \cdot 3^6 \cdot 3^8}{2^6 \cdot 3^6}$

$\textsf{Apply exponent rule} \quad a^b \cdot a^c=a^{b+c}:$

$\implies \dfrac{3^{(5+6+8)} \cdot 2^{(4+1)}}{2^6 \cdot 3^6}$

$\implies \dfrac{3^{19} \cdot 2^{5}}{2^6 \cdot 3^6}$

$\implies \dfrac{3^{19} \cdot 2^{5}}{3^6 \cdot 2^6}$

$\textsf{Apply exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:$

$\implies 3^{(19-6)} \cdot 2^{(5-6)}$

$\implies 3^{13} \cdot 2^{-1}$

$\textsf{Apply exponent rule} \quad a^{-n}=\dfrac{1}{a^n}:$

$\implies \dfrac{3^{13}}{2^1}$

$\textsf{Apply exponent rule} \quad a^1=a:$

$\implies \dfrac{3^{13}}{2}$

4 0

2 years ago

Simplify the expression 10a + 5b + 3 - 25a + 2b - 18 + 3b - 5a pls!!!

Scrat [10]

Answer:

−20a + 10b − 15

Step-by-step explanation:

The expression simplified is: −20a + 10b − 15

hope this helps

8 0

3 years ago

Which graph represents the function f(x)=x4+4x3−12x2−32x+64?

sp2606 [1]

$f(x)=x^4+4x^3-12x^2-32x+64$

The degree of f(x) is 4. Also the leading coefficient is 1 and it is positive

So as x approaches infinity then y approaches infinity

as x approaches -infinity then y approaches infinity

The first and fourth graph goes up and it satisfies the above . so we ignore the second and third graph.

Now we check the x intercepts of the first graph

x intercepts of first graph is -4 and 2

Plug in -4 for x in f(x) and check whether we get 0

$f(x)=x^4+4x^3-12x^2-32x+64$

$f(x)=(-4)^4+4(-4)^3-12(-4)^2-32(-4)+64=0$

Now plug in 2 for x and check

$f(x)=(2)^4+4(2)^3-12(2)^2-32(2)+64=0$

So -4 and 2 are the x intercepts that satisfies f(x)

Hence first option is the graph of $f(x)=x^4+4x^3-12x^2-32x+64$

5 0

3 years ago

Read 2 more answers

I needddd helppppppp

german

Answer:3,4,5

Step-by-step explanation:

8 0

3 years ago

154-54(79-1554)+12x24

RideAnS [48]

Answer:

80092

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers