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3 years ago

If a car reaches speeds of 0-100 mph in 0.8 seconds, how many mph will it reach in 1 second?

Mathematics

1 answer:

zvonat [6]3 years ago

4 0

Answer:

125 mph

Step-by-step explanation:

This can be calculated as a simple rule of 3.

In rule of 3 problems, you need to first identify the measures and whether they are direct or inverse to each other.

If they are direct to each other, if one value increases the other will increase too. For example, lets suppose that the Buffalo Bills have won 3 of 4 games. When there are 8 games, then will have won 6, keeping this proportion. Here, the measures are the number of games and the number of Buffalo Bills wins.

Now if they are inverse to each other, if one value increases the other will decrease. For example, if you travel at 60 mph, you will need 6 hours to arrive at your destination. At 80 mph, you will need less time. So, a the average speed increases, the time you need will decrease.

In this case the speeds is proportional to the time. So, if the time increases, the speed will increase too. It can be calculated by the following rule of 3.

Speed Time

100 mph - 0.8 seconds

x mph - 1 second

x = 100/0.8 = 125 mph.

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Crank

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4 0

3 years ago

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

$\int\limits^5_1 {x/(2+x^{3}) } \, dx$ =f(x)= $x/2+x^{3}$

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)= $[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}$

$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

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5 0

2 years ago

If U.S. Treasury bills are earning 4 percent and the stock investment you are considering has a potential return of 10 percent,

erica [24]

Answer:

Option "D" is the correct answer to the following question.

Step-by-step explanation:

Given:

Return on U.S.Treasury bills = 4%

Potential return on stock investment = 10%