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zlopas [31]
3 years ago
5

Read image for instructions

Biology
1 answer:
Volgvan3 years ago
6 0

Answer:

Image is not here????

u have not posted image in this question

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What phenotypic ratio would one would expect from crossing two heterozygous smooth kernel corn plants that show mendelian inheri
ExtremeBDS [4]

Answer:

Smooth kernel corn plant : wrinkled  kernel corn plant = 3:1

Explanation:

Mendelian inheritance follows the laws of segregation and independent assortment. Thus, there exists neither  co-dominance nor incomplete dominance.

Let the allele for smooth kernel trait of corn plants be represented by "S"

and the allele for wrinkled kernel trait of corn plants be represented by "s"

The genotype of  heterozygous smooth kernel corn plants  will be "Ss"

The offspring produced by crossing two heterozygous smooth kernel corn plants would be -

Ss * Ss

SS, Ss, Ss, ss

Out of four offspring , one offspring is  homozygous smooth kernel corn plant

Two offspring are heterozygous smooth kernel corn plants

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The phenotypic ration is

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6 0
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