Answer:
x² + 7x + 10 = 0
Subtract 10 from both sides
x² + 7x = -10
Use half the x coefficent (7/2) as the complete the square term
(x + 7/2)² = -10 + (7/2)²
note: the number added to "complete the square" is (7/2)² = 49/4
(x + 7/2)² = -10 + 49/4
(x + 7/2)² = 9/4
Take the square root of both sides
x + 7/2 = ±3/2
Subtract 7/2 from both sides
x = -7/2 ± 3/2
x = {-5, -2}
Answer:
B. (0, 5]∪(15,30] only (15,30] contains viable rates for the hoses.
Step-by-step explanation:
The question is incomplete. Find the complete question in the comment section.
For us to meet the pool maintenance company's schedule, the pool needs to fill at a combined
rate of at least 10 gallons per minute. If the inequality represents the combined rates of the hoses is 1/x+1/x-15≥10 we are to find all solutions to the inequality and identifies which interval(s) contain viable filling rates for the hoses. On simplifying the equation;



The interval contains all viable rate are values of x that are less than 30. The range of interval is (0, 5]∪(15,30]. Since the pool needs to fill at a combined rate of <em>at least 10 gallons per minute</em> for the pool to meet the company's schedule, <em>this means that the range of value of gallon must be more than 10, hence (15, 30] is the interval that contains the viable rates for the hoses.</em>
Answer:
B. 0.210
Step-by-step explanation:
Range is the minimum value subtracted from the maximum value. In this case 0.004 is the smallest value and 0.214 is the largest.
Range = 0.214 - 0.004 = 0.210 = B
Answer:
depended is the 6th grade
independed the 2/9 students
-by-step explanation:
Answer: 
Step-by-step explanation:
We can use the Rational Root Test.
Given a polynomial in the form:

Where:
- The coefficients are integers.
-
is the leading coeffcient (
)
-
is the constant term 
Every rational root of the polynomial is in the form:

For the case of the given polynomial:

We can observe that:
- Its constant term is 6, with factors 1, 2 and 3.
- Its leading coefficient is 2, with factors 1 and 2.
Then, by Rational Roots Test we get the possible rational roots of this polynomial:
