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Nezavi [6.7K]
3 years ago
8

8/5 minus 1/6 = i dont know the answer sorry

Mathematics
2 answers:
Alex73 [517]3 years ago
5 0

Answer:

1 and 13/30

Step-by-step explanation:

:)

(:

:)

(:

Hope this helps!

<3

-Josh

brainliest?

Scrat [10]3 years ago
5 0

Answer:

Step-by-step explanation: 8/5-1/6

Find a common denominator

48/30-5-30=43/30

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Which of the following statements correctly compares the median and range of their scores?
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Answer:

B

Step-by-step explanation:

because it’s not A, C, and D

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Solve. 2 = 4 times quantity z + 1<br> A. -4<br> B. -1/2<br> C. 1/4<br> D. 2
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4(z+1)=2
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CAN U PLZ ANSWER IT?
Vadim26 [7]
So you subtitute into the equation
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4 0
3 years ago
Read 2 more answers
30% discount at $300 purchase is
Molodets [167]

Answer:

Thus, a product that normally costs $300 with a 30 percent discount will cost you $210.00, and you saved $90.00. You can also calculate how much you save by simply moving the period in 30.00 percent two spaces to the left, and then multiply the result by $300 as follows: $300 x .

Step-by-step explanation:

3 0
3 years ago
Write two expressions with unlike denominators whose sum is x-3/x+2, I need help it is confusing for me.
skad [1K]

Answer:

\displaystyle A=\frac{x-2}{x+3}

\displaystyle B=\frac{-5}{(x+3)(x+2)}

Step-by-step explanation:

We need to find two expressions with unlike denominators what sum

\displaystyle S=\frac{x-3}{x+2}

Let's suppose one of the expressions is:

\displaystyle A=\frac{x-2}{x+3}

Now we subtract S minus A to find the other expression B:

\displaystyle B=S-A=\frac{x-3}{x+2}-\frac{x-2}{x+3}

Multiply the first fraction by x+3 and the second by x+2;

\displaystyle B=(x+3)\frac{x-3}{(x+3)(x+2)}-(x+2)\frac{x-2}{(x+3)(x+2)}

Operating:

\displaystyle B=\frac{x^2-9}{(x+3)(x+2)}-\frac{x^2-4}{(x+3)(x+2)}

Subtracting both fractions with like denominators:

\displaystyle B=\frac{x^2-9-(x^2-4)}{(x+3)(x+2)}

Simplifying:

\displaystyle B=\frac{-5}{(x+3)(x+2)}

Thus the two expressions are:

\displaystyle A=\frac{x-2}{x+3}

And

\displaystyle B=\frac{-5}{(x+3)(x+2)}

8 0
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