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Amanda [17]
3 years ago
10

How to add mixed numbers

Mathematics
2 answers:
Bingel [31]3 years ago
8 0
The answer would be 6 and 8/9
Gnoma [55]3 years ago
8 0
The answer is 6 8/9, because they have a common denominator so you just add the nominator, and for the whole number you add it regularly.
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Find the product of z1 and z2, where z1 = 5(cos 60° + i sin 60°) and z2 = 7(cos 210° + i sin 210°)
Verizon [17]

Answer:

cos210=cos(180+30)=−cos30=−√32 . sin210=sin(180+30)=−sin30=−12 . 3(cos210+isin210) =3(−√32)+3i(−12). −(32)√3−(32)i. My favourite way of seeing that sin30=12 and cos30=√32 is ...

Step-by-step explanation:

But that's what I say personally

3 0
3 years ago
Which number sentences show how to solve the problem?
exis [7]

72 ÷ 6 = 12 and 12 × 36 = 432 and 72 × 36 = 2,592 and 2,592 ÷ 6 = 432

8 0
3 years ago
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Which pair of numbers have a GCF of 2? Choose all answers that are correct. A. 10 and 2 B. 4 and 6 C. 6 and 12 D. 2 and 24
il63 [147K]
A.
<span>GCF(10; 2) = 2  /</span>factors of 10: 1, 2, 5, 10; factors of 2: 1, 2/

B.
GCF(4; 6) = 2  /factors of 4: 1, 2, 4; factors of 6: 1, <span>2, 3, 6/</span>

C.
GCF(6; 12) = 6  /factors of 6: 1, 2, 3, 6; factors of 12: 1, <span>2, 3, 4, 6, 12/</span>

D.
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</span>Answer: A, B and D.


8 0
3 years ago
Read 2 more answers
An someone help me on the bottom part
maw [93]
=,>,<,<,= convert them each to where they match in their units 
8 0
4 years ago
Math school is selling tickets to a play on the first day of ticket sales the school sold two adult tickets and three students t
Illusion [34]

Answer: the cost of an adult ticket is $9.

The cost of a child's ticket is $13

Step-by-step explanation:

Let x represent the price of one adult ticket.

Let y represent the price of one student ticket.

On the first day of ticket sales, the school sold two adult tickets and three students tickets for a total of $57. It means that

2x + 3y = 57- - - - - - - - - -1

The school took and $70 on the second day by selling two adult tickets and four student tickets. It means that

2x + 4y = 70- - - - - - - - - -2

Subtracting equation 2 from equation 1, it becomes

- y = - 13

y = 13

Substituting y = 13 into equation 1, it becomes

2x + 3 × 13 = 57

2x + 39 = 57

2x = 57 - 39 = 18

x = 18/2

x = 9

8 0
3 years ago
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