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lord [1]
3 years ago
11

Round 3,989.23655 to the nearest tenth

Mathematics
1 answer:
dedylja [7]3 years ago
7 0
This would be 3990 if you require a whole number but for a decimal it would be 3989.24
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b. If each square has a side length of 61 cm, write an expression for the surface area and another for the volume of the figure
Blababa [14]

Answer:

6*(61^2) and 61^3

Step-by-step explanation:

If the squares have a side length of 61 (assuming this is a cube) our surface area is 6*(61^2) because each side is a square and there are six sides.

As for the volume, we have 61^3.

Hope this was helpful.

~cloud

8 0
3 years ago
1a. Alex skateboards at a constant speed from his house to school 4 miles away. It takes him 15 minutes. What fraction represent
erastovalidia [21]
Minutes - 15/4
or
Seconds - 15/240
3 0
2 years ago
Rearrange the formula, a=1/2bh , to solve for b in terms of A and h.
Kryger [21]
Multiply both sides by 2 to cancel out the 1/2 and you get 2a=bh then divide both sides by h to isolate b and you get (2a)/h=b
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3 years ago
Joseph is reading a 32 page book he read 6 pages in 15 minutes if he continues to read at the same rate how long will it take hi
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3 0
2 years ago
Read 2 more answers
Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)
PtichkaEL [24]

Answer:

(x^{-3} )^{2}

x^6 x^{-12}

Step-by-step explanation:

(x^{3} x^{-6} )^{2} is the expression given to be solved.

First of all let us have a look at <u>3 formulas</u>:

1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}

Both the formula can be applied to the expression((x^{3} x^{-6} )^{2}) during the first step while solving it.

<u>Applying formula (1):</u>

(x^{3} x^{-6} )^{2}

Comparing the terms of (x^{3} x^{-6} ) with p^a \times p^b

p=x, a =3, b=-6

\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}

So, (x^{3} x^{-6} )^{2} is reduced to (x^{-3} )^{2}

<u>Applying formula (2):</u>

Comparing the terms of (x^{3} x^{-6} )^{2} with (p^a \times q^b)^c

p=q=x, a =3, b=-6, c=2

\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}

So, (x^{3} x^{-6} )^{2} is reduced to x^6 x^{-12}.

So, the answers can be:

(x^{-3} )^{2}

x^6 x^{-12}

8 0
3 years ago
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