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Dennis_Churaev [7]
3 years ago
14

While traveling at a constant speed in a car, the centrifugal acceleration passengers feel while the car is turning is inversely

proportional to the radius of the turn. If the passengers feel an acceleration of 8 feet per second per second when the radius of the turn is 80 feet, find the acceleration the passengers feel when the radius of the turn is 320 feet.
Mathematics
1 answer:
Kazeer [188]3 years ago
3 0

Answer:

Step-by-step explanation:

250 is the answer from a high schooler

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A relation is a function, if and only if, the x- values do not repeat in a given set.
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Which is the area of a parallelogram with a base of 13 centimeters and a height of 3 centimeters?
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4 0
3 years ago
On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove
gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

v = \frac{d}{t}

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time t_1, distance of d_1, v = 40. So

v = \frac{d}{t}

40 = \frac{d_1}{t_1}

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is v = 60.

On the first day, he drove 2 more hours, which means that for the second day, the time is: t_1 - 2

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: d_1 - 20

Thus

v = \frac{d}{t}

60 = \frac{d_1 - 20}{t_1 - 2}

System of equations:

Now, from the two equations, a system of equations can be built. So

40 = \frac{d_1}{t_1}

60 = \frac{d_1 - 20}{t_1 - 2}

Find the total distance traveled in the two days:

We solve the system of equation for d_1, which gets the distance on the first day. The distance on the second day is d_2 = d_1 - 20, and the total distance is:

T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20

From the first equation:

d_1 = 40t_1

t_1 = \frac{d_1}{40}

Replacing in the second equation:

60 = \frac{d_1 - 20}{t_1 - 2}

d_1 - 20 = 60t_1 - 120

d_1 - 20 = 60\frac{d_1}{40} - 120

d_1 = \frac{3d_1}{2} - 100

d_1 - \frac{3d_1}{2} = -100

-\frac{d_1}{2} = -100

\frac{d_1}{2} = 100

d_1 = 200

Thus, the total distance is:

T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0
3 years ago
Melania has two jobs. During the day she works as an office clerk, and in the evening she works as a cashier. her office job pay
bulgar [2K]
Lets x = # of hours Melania  works at <span>office clerk
and y = </span># of hours Melania  works as a <span>cashier

x + y = 38 so x = 38 - y
13x + 9.25y = 434

substitute </span> x = 38 - y into 13x + 9.25y = 434

13x + 9.25y = 434
13(38 - y) + 9.25y = 434
494 - 13y + 9.25y = 434
                  -3.75y = -60
                          y = 16
x = 38 - y so x = 38 - 16 = 22

answer
Melania  works at office clerk = 22 hours
Melania  works as a cashier = 16 hours
7 0
3 years ago
Can someone please!!! Help me
timurjin [86]
The answer to this question is true
7 0
3 years ago
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