Ask question

Ask question

All categories

2 years ago

12

Suppose you spend $23, and you pay with a $50 bill. The cashier gives your change in bills. List all the different ways you can

receive your correct change if you will not take more than 10 bills, and the cashier only has 1s, 5s, and 10s. Show your work.

1 answer:

Aleksandr [31]2 years ago

3 0

Here are some answer i can think of: 2-10$ 1-5$ 2-1$, 6-5$ 2-1$, 27-1$, 1-10$ 3-5$ 2-1$

You might be interested in

<img src="https://tex.z-dn.net/?f=%5Clarge%5Csf%5Cfbox%5Cred%7BQuestion%3A-%7D" id="TexFormula1" title="\large\sf\fbox\red{Quest

tamaranim1 [39]

Answer:

The function is injective but nor surjective

Step-by-step explanation:

<u>We see that:</u>

f(x) = x³

<u>For any x₁ and x₂ ∈ N, </u>

f(x) = x₁³ = x₂³ ⇒ x₁ = x₂, both are natural numbers

It it confirmed one-to-one, hence it is injective

<u>Check the surjectivity:</u>

f(x) = y ∈ N

x³ = y
y = ∛x

<u>Let y = 2, then:</u>

2 = x³
x = ∛2 ∉ N

Since x is not natural, the function is not surjective

6 0

2 years ago

Read 2 more answers

Write the correct proportion.<br><br> 5 is to 19 as x is to 250

Alja [10]

This problem is basically asking:

$\frac{5}{19} =\frac{x}{250}$

Which would mean $x=\frac{5*250}{19}=\frac{1250}{19}$

7 0

3 years ago

Read 2 more answers

In a certain Algebra 2 class of 29 students, 7 of them play basketball and 14 of them

Mariulka [41]

Answer:

<em>Two possible answers below</em>

Step-by-step explanation:

<u>Probability and Sets</u>

We are given two sets: Students that play basketball and students that play baseball.

It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.

This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

$\displaystyle P=\frac{19}{29}$

P = 0.66

Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:

We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.

Thus, there 19-2=17 students who play only one of the sports. The probability is:

$\displaystyle P=\frac{17}{29}$

P = 0.59

3 0

3 years ago

The zeros of a quadratic function are -8 and 5. Write the quadratic function in Standard Form.

nataly862011 [7]

Answer:

y = x² + 3x - 40

Step-by-step explanation:

Given the zeros are x = - 8 and x = 5, then the factors are

(x + 8) and (x - 5) and

y = (x + 8)(x - 5) ← expand factors

y = x² - 5x + 8x - 40, hence

y = x² + 3x - 40 ← in standard form

7 0

2 years ago

Let f(r) = 6,<br> find f-¹(r)

I am Lyosha [343]

There is no answer because there cannot be one to one function inverse.

8 0

1 year ago