Question

M^ 2 + m − 90 factorize

Answer 1

Answer:

(m+10)(m-9)

Step-by-step explanation:

To factor this equation we want to find two numbers that multiply to -90 but also add/subtract to 1.

Those two numbers are 10 and -9 (10×-9=-90, 10-9=1)

Answer 2

Answer:

$(m-9)(m+10)$

Step-by-step explanation:

When you are given an expression in this format

$ax^2+bx+c$

You must find two numbers that add up to b while the product is c.

You do trial and error to figure it out for your equation.

$m^2+m-90$

Hmm... what two numbers add up to 1 and multiplied together equal -90.

Start off with pairs that can equal 90.

45 2

18 5

9 10

Ok, well 45 * 2 does equal 90 but 45 + 2 = 47and 45 + -2 = 43 but there's no way I can make it equal to 1. Next!

18 * 5 equals 90 but 18 + -5 = 13 and 18 + 5 = 23, I can just tell that there's no way I can make this equal to 1.

9 * 10 equals 90, 9 + 10 = 19 but 9 + -10 = -1. Now, that's interesting, We have -1 but we need 1. All we have to do is flip the order. 10 + -9 = 1. And -9 * 10 = -90, PERFECT!

Now use the two numbers and put it in factored form.

$(m-9)(m+10)$