This is an easy question you shouldn’t have to ask this on here.
Answer: x = 3, y = 2
Step-by-step explanation:
The line should pass through x = 3 and y = 2. Just like in the picture. I used a graphing app.
The given equation is 
By solving the given equation, we get


While solving the equation,we get 0=0.
Therefore, the given equation is true for all the values of y.
Hence, we can say that the given equation has infinite number of solutions.

It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if
</span><span>

</span><span>In notation we write respectively
</span>

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence

Thus these two limits, the one from above and below are equal if and only if
4c + 20 = 16 - c²<span>
Or in other words, the limit as x --> 4 of f(x) exists if and only if
4c + 20 = 16 - c</span>²

That is to say, if c = -2, f(x) is continuous at x = 4.
Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers 
For this case, the first thing we must do is define variables.
We have then:
x: number of times Giselle uses the athletic club
b: amount of money remaining
We write a linear equation of the form:
b = mx + c
Where,
m: slope of the line that represents the cost for each time she uses the athletic club
c: initial amount that Giselle paid
Substituting values we have:
b = -10x + 190
Answer:
a linear function that model the situation is:
d. b = 190 - 10x