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2 years ago

I AM GENEROUS PLZ HELP BRAINLIEST

Biology

2 answers:

masha68 [24]2 years ago

6 0

Answer:

replication or mitosis

const2013 [10]2 years ago

4 0

Answer:::::::::::: Meiosis………

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assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar

svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

$E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}} \Big )$

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

$E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}$

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

$100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\ 53.57 = \dfrac{4}{[K^+]_{in}}$

$[K^+]_{in} = \dfrac{4}{53.57}$

$[K^+]_{in} = 0.0476$

For [Cl⁻]:

$100 \times 10^{-3} = -0.0257 \ \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}} \Big)$

$-3.981 = \ \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}} \Big)$

$0.01867 = \dfrac{120}{[Cl^-]_{in}}$

$[Cl^-]_{in} = \dfrac{120}{0.01867}$

$[Cl^-]_{in} =6427.4$

For [Na⁺]:

$100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}} \Big)$

$53.57= \Big ( \dfrac{145}{[Na^+]_{in}} \Big)$

$[Na^+]_{in}= 2.70$

6 0

2 years ago

Individual 6 had the same MtDNA as...

jok3333 [9.3K]

C: individual #2 that is your answer

4 0

3 years ago

What of the following is ordered from LARGEST to SMALLEST? Select one: a. virus, mitochondrion, hemoglobin, glucose, water molec

choli [55]

Answer:

c. mitochondrion, virus, hemoglobin, glucose, water molecule

Explanation:

The mitochondrion is a membrane which is found in cytoplasm of eukaryotic cells. It is also known as power house of cells. This is largest from virus, hemoglobin, water molecule and glucose.

Virus is second largest and is small infectious agent. It has capability to infect many organisms and living cells. Hemoglobin is protein which is present in red blood cells. Glucose is a type of sugar presence in the blood. Water molecule is composed of hydrogen and oxygen and is smallest among the others.

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3 years ago

g In transcription, the 3'-hydroxyl group of the growing RNA strand: Group of answer choices NONE OF THESE binds to the 5' ribos

Tatiana [17]

Answer:

attacks the outermost phosphorous group of the incoming nucleotide.

Explanation:

Transcription is the biological process where RNA is formed. As you may already know, RNA is an extremely important nucleic acid for genetic processes and the production of proteins. The transcription has three steps that are called start, elongation and end. In the elongation phase, the RNA strand is growing, at this time, RNA polymerase, which is the enzyme responsible for RNA elaboration, places the nucleotides, in the RNA strand, in the 5' - 3' direction. This enzyme causes the hydroxyl, which makes up the nucleotide at the 3' end of the forming RNA, to attack the phosphorus present in the incoming ribonucleotide.

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3 years ago

#1 About how much energy is transferred from a primary consumer to a secondary consumer?

mezya [45]

#1 c
#2 c
#3 a
#4 a
I hope im right!

4 0

3 years ago

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