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2 years ago

Find an expression for the area enclosed by quadrilateral ABCD below.

Mathematics

2 answers:

Helga [31]2 years ago

6 0

∆ABD is right angled hence area:-

$\\ \sf\longmapsto \dfrac{1}{2}bh$

$\\ \sf\longmapsto \dfrac{1}{2}(4x)(3x)$

$\\ \sf\longmapsto \dfrac{1}{2}(12x^2)$

$\\ \sf\longmapsto 6x^2$

There is only one option containing 6x^2 i.e Option D.

Hence without calculating further

Option D is correct

steposvetlana [31]2 years ago

5 0

Answer:

Check the picture uploaded

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What is 15-5(4x-7)=50

katovenus [111]

Simplifying

15 + -5(4x + -7) = 50

Reorder the terms:

15 + -5(-7 + 4x) = 50

15 + (-7 * -5 + 4x * -5) = 50

15 + (35 + -20x) = 50

Combine like terms: 15 + 35 = 50

50 + -20x = 50

Add '-50' to each side of the equation.

50 + -50 + -20x = 50 + -50

Combine like terms: 50 + -50 = 0

0 + -20x = 50 + -50

-20x = 50 + -50

Combine like terms: 50 + -50 = 0

-20x = 0

Solving

-20x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-20'.

x = 0.0

Simplifying

x = 0.0

5 0

2 years ago

Write an equation that represents the line passing through the point -3, -1 with a slope of 4

Alex17521 [72]

Answer:

Equation that represents the line passing through the point -3, -1 with a slope of 4 is

$y= 4x+11$

Step-by-step explanation:

Equation of line in point slope form is

$y-y_1=m(x-x_1)$ -------(1)

Here

$m=4 \ \ \ and \ \ \ (x_1, y_1) = (-3, -1)$

Substituting values in equation (1)

$y+1=4(x+3)\\ y= 4x+11$

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5C%7B%20%5Cfrac%20%7B%20%28%20%5Csqrt%20%7B%203%20%7D%20%29%20%5Ctimes%203%20%5E%20%7B%20-%20

ZanzabumX [31]

Answer:

Step-by-step explanation:

Exponent law:

$\sf \bf a^m * a^n = a^{m+n}\\\\ (a^m)^n = a^{m*n}$

$\sf a^{-m}=\dfrac{1}{a^m}$

First convert radical form to exponent form and then apply exponent law.

$\sf \sqrt{3}=3^{\frac{1}{2}}\\\\\sqrt{5}=5^{\frac{1}{2}}$

$\sf \left(\dfrac{(\sqrt{3}*3^{-2}}{(\sqrt{5})^2}\right)^{\frac{1}{2}}= \left(\dfrac{3^{\frac{1}{2}}*3^{-2}}{(5^{\frac{1}{2}})^2} \right )^{\frac{1}{2}}$

$= \left(\dfrac{3^{\frac{1}{2}-2}}{5^{\frac{1}{2}*2}}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{1-4}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{-3}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\dfrac{3^{\frac{-3}{2}*{\frac{1}{2}}}}{5^{\frac{1}{2}}}\\\\ =\dfrac{3^{{\frac{-3}{4}}}}{5^{\frac{1}{2}}}$

3 0

1 year ago

Base of triangle exceeds the height by 4. If the area is 178.5 square inches, find the length of the base and the height of the

xxMikexx [17]

Area of a triangle:
A= (1/2)(bh)

In this problem we are given:
A= 178.5 $in^{2}$
b= h+4 in
h= UNKNOWN ("h")

Plug in our values into the area equation and solve for "h":
$A= \frac{1}{2} bh$
$178.5 = \frac{1}{2} ((h+4)h)$ (multiply each side by 2 to get rid of the 1/2)
$357 = ((h+4)h)$
$357 = h^{2} +4h$
$0= h^{2} +4h -357$
(357/21=17)
$0= (h+21)(h-17)$ (solve both inequalities separately)

$0= (h+21)$
$-21= h$ ( a negative height is not possible so, this answer is incorrect.)

$0=(h-17)$
$h=17 in$

Answer: base = (h+4)= (17+ 4) b= 21 in h= 17in

Please comment with any further questions! :)

5 0

2 years ago

He<br> Find the volume of this cylinder. Use 3 for pi<br> V = ?

Alborosie

Answer:

30in^3

Step-by-step explanation:

3x1^2x10=

3x1x10=

30in^3

3 0

2 years ago

Read 2 more answers