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Bogdan [553]
3 years ago
12

A university's leadership council is made up of 10 members: 3 are students, 3 are teachers, and 4 are deans. A newspaper reporte

r is planning to select two of
the council members for Interviews. The first member will be chosen at random, and then the second member will be chosen at random from the remaining
members. What is the probability that two students will be selected?
Report your answer as an exact fraction.
Mathematics
1 answer:
Vlad [161]3 years ago
7 0

Answer:

1/15

Step-by-step explanation:

First you must figure out your total outcomes, int the problem it said ten. Than take the number of students and put the number of students over the number of outcomes. This will tell you the probability of drawing one student. Next you must subtract 1 student and one member from your original equation. This is because you have assumed that the first drawing had a favorable outcome. So that leaves you with 2/9. Next you must multiply both the first fraction (3/10) and the second fraction (2/9) to come up with the total probability of the event occurring.

Hope that helped.  

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Step-by-step explanation: Hope this help(:

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Sophia has an ear infection. The doctor prescribes a course of antibiotics. Sophia is told to take 500 mg doses of the antibioti
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Answer:

Step-by-step explanation:

Part 1:

Let 

     Q₁ = Amount of the drug in the body after the first dose.

     Q₂ =  250 mg

As we know that after 12 hours about 4% of the drug is still present in the body.

For Q₂,

we get:

            Q₂ = 4% of Q₁ + 250

                  = (0.04 × 250) + 250

                  = 10 + 250

                  = 260 mg

Therefore, after the second dose, 260 mg of the drug is present in the body.

Now, for Q₃ :

We get;

          Q₃ = 4% of Q2 + 250

               = 0.04 × 260 + 250

               = 10.4 + 250

               = 260.4

For Q₄,

We get;

          Q₄ = 4% of Q₃ + 250 

                = 0.04 × 260.4 + 250

                = 10.416 + 250 

                = 260.416

Part 2:

To find out how large that amount is, we have to find Q₄₀.

Using the similar pattern

for Q₄₀,

We get;

           Q₄₀ = 250 + 250 × (0.04)¹ + 250 × (0.04)² + 250 × (0.04)³⁹

Taking 250 as common;

           Q₄₀ = 250 (1 + 0.04 + 0.042 + ⋯ + 0.0439)

                 = 2501 − 0.04401 − 0.04

           Q₄₀ = 260.4167

Hence, The greatest amount of antibiotics in Susan’s body is 260.4167 mg.

Part 3:

From the previous 2 components of the matter, we all know that the best quantity of the antibiotic in Susan's body is regarding 260.4167 mg and it'll occur right once she has taken the last dose. However, we have a tendency to see that already once the fourth dose she had 260.416 mg of the drug in her system, that is simply insignificantly smaller. thus we will say that beginning on the second day of treatment, double every day there'll be regarding 260.416 mg of the antibiotic in her body. Over the course of the subsequent twelve hours {the quantity|the quantity|the number} of the drug can decrease to 4% of the most amount, that is 10.4166 mg. Then the cycle can repeat.

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